Example 1 — 5×4 m slab
- 5 × 4 × 0.1 m
- +5% waste
- 0 deductions
2.1 m³
A basic slab case where volume is the starting point for ordering and cost planning.
Volume from length × width × height × count, minus deductions, plus waste %.
Also useful: mortar requirement, cement in mortar.
Enter data and click Calculate.
V = length × width × height × count × (1 + waste/100), then subtract deducted volume. The result is floored at 0.
2.1 m³
A basic slab case where volume is the starting point for ordering and cost planning.
2.2 m³
With larger pours, even a modest waste allowance can change cost and delivery planning.
0.567 m³
Shows why counting identical elements early helps when timing a pour.
Volume = length × width × height × count, minus deductions, then × (1 + waste%). Example: 5×4×0.1 m → 2 m³, +5% waste → 2.1 m³.
Volume of embedded elements or openings that displace concrete (e.g. pipes, blockouts), in the same volume unit.
For repeated identical pours (posts, footings) count multiplies the single-unit volume before waste.
Divide the total volume by a standard 6 m³ ready-mix truck load and round up to plan deliveries.
Typically 5–10% for slabs and footings to cover spillage and formwork tolerance.
Use the units selector in the header. Labels and examples update automatically.
Yes, especially if the substrate is not perfectly even or there is a risk of small execution differences.
Most often cost, bag count, or transport/load planning depending on how the work will be carried out.