Example 1
- Radius: 5
- Height: 10
785.40
What volume at r = 5 and h = 10? ≈ 785.40.
Enter the radius r of the circular base and the height h. The calculator computes the volume of a right circular cylinder with V = πr²h. At r = 5 and h = 10 the result is about 785.40; at r = 3 and h = 8 about 226.19. The form takes radius, not diameter — for diameter 10 divide by 2 first.
Enter radius r and height h greater than zero.
Domain: r > 0 and h > 0 in the same length unit. This is not lateral area 2πrh or volume from circumference C²h/(4π). The result uses two decimal places.
A right circular cylinder has two parallel circular bases of equal radius r and a lateral surface perpendicular to those bases. The classical volume is V = πr²h: the disk area πr² times the height h measured perpendicularly between the bases. This calculator takes radius r and height h directly — without going through circumference. The constant π comes from circle geometry; the calculator uses π, not the fraction 22/7.
The domain is simple: r > 0 and h > 0. Zero or a negative value does not describe a solid cylinder with positive volume here — the calculator shows a message instead of inventing a result. An empty field leaves the result blank. Commas and periods in the fields are equivalent. The unit switch only changes unit labels on the result (cm/cm³ or in/in³); it does not multiply or divide the numbers you enter.
The calculator uses the numbers you enter: radius r and height h. The result panel shows r, r², h, base area πr², and volume V. At r = 5 and h = 10 you get π·25·10 = 250π ≈ 785.40. The unit cylinder r = 1, h = 1 gives π ≈ 3.14. A short wide drum r = 10 and h = 2 gives 200π ≈ 628.32.
If a worksheet gives diameter instead of radius, divide by two before you enter r. Diameter 10 means r = 5; entering 10 as r with h = 10 overstates volume by four because r is squared. A cone with the same r and h holds one third of this volume. A sphere at a lone r does not use h. Lateral area 2πrh and volume from circumference C²h/(4π) live on separate pages.
Historically, Archimedes in On the Sphere and Cylinder studied volume ratios of a sphere and a cylinder circumscribed about that sphere (the sphere volume is 2/3 of that cylinder). That is not the formula behind the form fields — it is context for solids of revolution. The formula V = πr²h belongs to standard solid geometry in school and university texts (including MathWorld — Cylinder and OpenStax).
A pancake r = 10 and h = 2 is a legal cylinder: a large circle, a small height. A slim pipe r = 2 and h = 10 is too. The formula does not need r and h to look alike. If you only want circle area, stay on the circle page; here height always goes in.
V = π × r² × h, equivalently V = πr²h.
Symbol r is the radius of the circular base (first field). Symbol h is the cylinder height. The constant π comes from circle geometry. Domain: r > 0, h > 0.
Mathematical model: right circular cylinder volume. Sources: standard solid geometry; MathWorld — Cylinder; OpenStax; Archimedes context in On the Sphere and Cylinder.
The volume of a right circular cylinder is V = πr²h, where r is the radius of the circular base and h is the height measured perpendicularly between the bases. This calculator takes r and h directly. Units must stay consistent: if r and h are in inches, the result is in cubic inches.
A right circular cylinder has circular bases of equal radius and generators perpendicular to the base planes. The formula V = πr²h is the volume of the solid of revolution obtained by rotating a rectangle about one side. It is an exact geometric formula under the ideal-circle, constant-height assumptions — not an engineering approximation.
Cylinder volume is among the oldest solid-geometry results. In On the Sphere and Cylinder Archimedes proved, among other facts, that a sphere has two-thirds the volume of the circumscribed cylinder and two-thirds of that cylinder’s total surface; those ratios already assume V_cylinder = πr²h. Euclid’s Elements (Book XII) treats cylinders and cones by exhaustion, comparing solids of equal height.
Conceptually the calculator does not infer material or pressure — it computes only the geometric interior volume of an ideal cylinder. If the cross-section is not a circle or the height is not constant, πr²h no longer applies. With diameter d = 2r the equivalent form is V = (πd²/4)h.
Input domain: r > 0, h > 0 (and finite floating-point numbers in practice). For r ≤ 0 or h ≤ 0 the geometric volume is not positive as a solid. Homogeneity: if every length is scaled by λ > 0, then r′ = λr, h′ = λh and V′ = λ³V, matching the dimension of volume.
At fixed r, V(h) = πr²·h is linear; at fixed h, V(r) grows like r². Relative sensitivity: ∂V/V = 2 ∂r/r + ∂h/h, so a relative radius error enters with weight 2. Base area A = πr², so V = A·h — the product of base area and height.
Step 1. The area of a circle of radius r is A = πr². The constant π is the ratio of circumference to diameter.
Step 2. A right cylinder with circular base and height h has volume equal to base area times height: V = A·h = πr²h. This follows from Cavalieri’s principle: every cross-section parallel to the base has constant area A.
Step 3 (consistency with diameter). With d = 2r you get V = (πd²/4)h = πr²h. With circumference C = 2πr the same volume is C²h/(4π) — a separate page when you know C instead of r.
Step 4 (cone). A cone with the same r and h has volume (1/3)πr²h, one third of the cylinder. That is not this form’s output — only a geometric comparison.
When r = 1 and h = 1, V = π ≈ 3.14 (the unit cylinder). When r = 5 and h = 10, V = 250π ≈ 785.40. When r = h = 4, V = 64π ≈ 201.06. The limit h → 0 yields V → 0 (a flattened cylinder). The limit r → 0 at fixed h also yields V → 0.
A square-cross-section prism needs a different formula (area = a², not πr²). A pipe of wall thickness δ needs a hollow-cylinder model: the difference of outer and inner volumes, not πr²h with the outer radius alone.
The calculator uses π in floating-point arithmetic and rounds the result to two decimal places, matching the worked examples on the page. Very large r²h may overflow the floating-point range; typical user dimensions are safe. The order π·r·r·h is algebraically equivalent to (πr²)h.
The code evaluates V = π · r · r · h. At r = 5 and h = 10: r² = 25, πr² ≈ 78.54, V = 250π ≈ 785.40. At r = 3 and h = 4: V = 36π ≈ 113.10.
Commas and periods in the fields are equivalent. The calculator does not model a cone, an oblique cylinder, or finite wall thickness. For an oblique cylinder the volume is still πr²h with perpendicular height (Cavalieri), but the slant is not h — this form assumes a right cylinder.
Related models on this site: circle area (πr²), cylinder volume from circumference (C²h/(4π)), cylinder lateral area (2πrh), cone volume ((1/3)πr²h), and sphere volume ((4/3)πr³). This formula computes only the volume of a solid right circular cylinder from r and h.
A cone with the same r and h has volume (1/3)πr²h — one third of this cylinder; a separate calculator applies the factor 1/3. Lateral area 2πrh and total surface area are different questions. Do not confuse height h with the slant length along the lateral surface.
Sources: Archimedes, On the Sphere and Cylinder (Heath); Euclid, Elements, Book XII; NIST DLMF (π); MathWorld — Cylinder; OpenStax — volume of cylinders; Wikipedia — Cylinder (geometry). The calculator is an educational tool and does not replace engineering standards for pressure vessels.
Cylinder volume: V = πr²h. At r = 5 and h = 10 the result is 785.40.
785.40
What volume at r = 5 and h = 10? ≈ 785.40.
3.14
What volume at r = 1 and h = 1? ≈ 3.14 — same as circle area at r = 1.
226.19
What volume at r = 3 and h = 8? ≈ 226.19.
125.66
What volume at r = 2 and h = 10? ≈ 125.66.
615.75
What volume at r = 7 and h = 4? ≈ 615.75.
201.06
What volume at r = 4 and h = 4? ≈ 201.06.
628.32
What volume at r = 10 and h = 2? ≈ 628.32.
1357.17
What volume at r = 6 and h = 12? ≈ 1357.17.
Radius r and height h must both be greater than zero. The calculator rejects zero and negative values — they do not define a solid cylinder with positive volume in this model. An empty field leaves the result blank, not zero.
The volume is 785.40. That is 250π rounded to two decimal places: π·5²·10 = 250π. Base area at that r is 78.54; times height 10 gives the volume. The same figure appears in example 1 and in the press-seed paragraph.
From the geometry of a right circular cylinder: volume is the area of the circular base times height. Circle area is πr², so V = πr²h. The calculator uses π, not the fraction 22/7, and shows two decimal places.
Circle area is πr² (an area unit). Volume multiplies that area by height h. At r = 5 the area is 78.54; at h = 10 the volume is 785.40.
Arithmetically the result is 250π. The page rounds to two decimals. The formula still uses π, not 22/7.
Divide the diameter by two first. Diameter 10 means r = 5. Entering 10 as r with h = 10 overstates volume by four because r is squared.
Radius and height must share one length unit. With Metric the labels are cm and cm³; with US they are in and in³. The header switch changes labels only — it does not convert the numbers you entered.
No. The currency and unit settings in the page header do not affect this result. Only r, h and π matter.
A cone with the same r and h holds one third of the volume. At r = 5 and h = 10 the cylinder is 785.40 and the cone is 261.80. That is a separate cone volume page.
This is volume in cm³ or in³. The wrap-around label is lateral area 2πrh on the cylinder lateral area page. Volume from base circumference is on a separate C²h/(4π) page.
Yes. 5.5 and 5,5 are the same radius. Spaces inside a number are ignored.
In On the Sphere and Cylinder Archimedes compared the volumes of a sphere and a cylinder circumscribed about that sphere. This calculator only computes cylinder volume V = πr²h — the citation is historical context, not a separate form formula.
Square the radius, multiply by π (base area), then by height. At r = 5 and h = 10: π·25·10 = 250π ≈ 785.40. At r = 3 and h = 8: π·9·8 ≈ 226.19.
First r = d / 2, then V = πr²h (or V = πd²h / 4). Diameter 10 and h = 10 mean r = 5 and volume ≈ 785.40. On this page enter r already — do not put d in the radius field.
When r and h are in centimetres, the result is in cm³: divide by 1000, because 1 L = 1000 cm³. Example: 785.40 cm³ ≈ 0.785 L. This page reports cubic units from the label — it does not convert to litres separately.
Because the formula uses r². At r = 5 and h = 10 volume ≈ 785.40; at r = 10 and h = 10 ≈ 3141.59 — about four times larger. Height scales linearly: doubling h doubles V.
With the same r and h a cone holds one third of the cylinder’s volume. At r = 5 and h = 10 the cylinder is ≈ 785.40 and the cone ≈ 261.80 — a separate cone volume page.
The formula, derivation, and historical context below come from recognized geometry sources.
Page Updated November 2, 2026.