Article

Uniform motion

Speed constant in time. Know any two of v, s, t — the third follows from s = v·t.

Part 1 of Physics without mysteries. Next: accelerated motion.

How it works

Uniform motion is the simplest model: speed does not rise or fall. Hold a steady 20 m/s for 90 s and the distance is 1800 m — period. The s(t) graph is a straight line; Galileo already wrote about “equal pace” in the Dialogues (1638).

School tools get mixed up. The v–s–t solver fills any two fields. “Distance only” always computes s = v·t from two inputs. Average speed divides whole distance by whole time including traffic — that is not the speedometer reading.

Practical note: “I was doing ninety” is often instantaneous speed. If there were lights on the route, use average speed. This article and the solver assume v really was constant, or that you knowingly use the ideal school model.

Which formula when

SituationFormulaWhen
Know v and ts = v·tDistance at constant speed
Know s and tv = s/tSpeed (here: constant = average)
Know s and vt = s/vTravel time with no stops
Whole trip with trafficv̄ = s/tAverage speed — different calculator

Solved problems

Highway distance

A car travels at constant speed v = 20 m/s for t = 90 s. What distance does it cover?

Steps

  1. Use uniform motion: v = const.
  2. Write s = v·t.
  3. Substitute: s = 20 · 90.
  4. Compute: s = 1800 m (= 1.8 km).
  5. Check in the calculator: fill v and t, leave distance blank.

Answer: s = 1800 m

Fill in the calculator

Time from known s

At constant v = 25 m/s you need to cover s = 5000 m. How long does it take?

Steps

  1. Formula: t = s/v.
  2. Substitute: t = 5000 / 25.
  3. Result: t = 200 s (= 3 min 20 s).
  4. Units: metres and m/s give seconds.
  5. Fill s and v in the solver.

Answer: t = 200 s

Fill in the calculator