Example 1
Cruise control 113 km/h (31.3 m/s) for 1.5 h: how far?
Enter any two of three: speed, distance, time. The calculator computes the missing one from s = v·t at constant v. 33.3 m/s for 3600 s is about 120,000 m, or 120 km of driving with no stops.
Speed v, Distance s and Time t. The result shows up here.
Uniform motion is constant speed: s = v·t, v = s/t, t = s/v. 120 km/h is 33.3 m/s. Over 3600 s that is about 120,000 m, or 120 km. You type two fields and leave the third as the unknown. At 6 m/s over 36,000 m the time is 6000 s. At 8 m/s over 480 m the time is 60 s.
Speed and distance take units from the labels. Time is in seconds unless the label says otherwise. An hour is 3600 s, not 1. 120 in a m/s speed field is 120 m/s, over 400 km/h, not one hundred twenty on the dial. A comma and a period are the same v: 33,3 and 33.3.
Exactly two fields need a number. Three filled fields are rejected, because the calculator cannot tell what to solve. Two unknowns are not enough. Zero speed with a nonzero distance does not give a finite time: you never arrive. Typed 0 in s with a nonzero v gives t = 0.
Acceleration and average speed with stops live next door. Here v does not drop at lights. The sibling card only does s = v·t; here you can also get v or t. Kinetic energy ½mv² is another story: distance here, not joules.
The English card’s 31.3 m/s for 5400 s (1.5 h) is about 169 km. A 240,000 m stretch in 4320 s is a steady about 55.6 m/s. Type those example pairs and match the notebook.
Pick the unknown, fill the other two, click Calculate. 33.3 and 3600 give about 120,000 m. The header symbol does not drive for you. You pick the Missing quantity, then type the rest.
Distance only at constant v: s = v·t. With stops: average speed.
s = v · t
Also v = s / t and t = s / v. Two fields filled, the third empty.
Uniform motion in this calculator wants two fields filled and one blank. s = v·t, so also v = s/t and t = s/v, no acceleration.
Cruise control 113 km/h (31.3 m/s) for 1.5 h: how far?
A 240000 m stretch in 1 h 12 min: what constant speed?
36000 m of flat road at 6 m/s: how long?
Steady 8 m/s over 480 m, travel time?
9000 m in 45 min: what speed?
Pace 4 m/s for 12.5 min: distance?
22000 m at a steady 12 m/s: time?
250 m/s for 40 min: distance covered?
s = 33.3 × 3600 ≈ 120,000 m, or 120 km. 120 km/h is about 33.3 m/s. At 31.3 m/s for 5400 s you get about 169 km on the English page.
Exactly two. The third is the unknown. Three numbers at once are rejected, because the calculator cannot tell which quantity to solve.
The labeled ones. v is often m/s. 120 km/h is 33.3 m/s, not 120 in a m/s field. Time is usually seconds: an hour is 3600.
Blank is the unknown. Typed 0 in v with nonzero s does not give a finite t. Typed 0 in s gives t = 0.
On the average-speed page. Here v does not drop at lights. This calculator assumes one constant speed.
That page only does s = v·t. Here you can also get v or t, as long as you fill exactly two fields.
Yes. 33,3 and 33.3 are the same speed. The calculator does not require a period.
On the acceleration page or accelerated motion. Here a = 0. Speed does not rise or fall.
Only if the label is km/h. In m/s that is 120 m/s, over 400 km/h. Convert 120 km/h to 33.3 m/s first.
t = 480 / 8 = 60 s. For 36,000 m at 6 m/s that is 6000 s. Both pairs sit on the example cards.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.