Example 1
A constant 33.33 m/s for 5,400 s, which is 1.5 h. The missing quantity is distance.
s = 179,982.00 m
Enter exactly two of the three quantities: speed v, distance s, and time t. The calculator finds the missing one from s = v·t at constant v. At 33.33 m/s for 5,400 s the distance is 179,982.00 m. The model does not include acceleration or stops.
Enter exactly two of the three quantities. The missing quantity, the other two, and the distance chart will appear here.
Distance alone, in km/h and hours, is on the distance calculator. A trip that includes stops belongs on the average speed calculator. Speeding up belongs on the uniformly accelerated motion calculator.
Uniform rectilinear motion is motion in which the speed does not change with time. The calculator finds the missing one of three quantities from s = v·t, v = s/t, and t = s/v. For v = 33.33 m/s and t = 5,400 s the product is 33.33 × 5,400 = 179,982 m. The panel shows a distance of 179,982.00 m, a speed of 33.33 m/s (120.0 km/h), and a time of 5,400.00 s (90.00 min).
The calculator uses the numbers you enter: speed v in m/s, distance s in meters, and time t in seconds. A blank field is the unknown and does not mean zero. Enter exactly two quantities. At 6.00 m/s over 36,000 m the time is 6,000.00 s (100.00 min). At 8.00 m/s over 480 m the time is 60.00 s (1.00 min). For 240,000 m in 4,320 s the speed is 55.56 m/s (200.0 km/h).
What the result panel shows. Besides the missing quantity, the calculator reports speed, distance, and time after it solves, rounded the same way as the main result. Speed is given in m/s and in km/h. A time of 60 s or more also shows minutes. The chart draws distance against time: at constant v that graph is a straight line. A comma and a period in a field mean the same number.
Limits of the model. The formula assumes one constant speed along a straight line. It does not include stops, drag, or gear changes. The average speed calculator divides the whole distance by the whole time, stops included. The distance calculator finds only s = v·t, with speed in km/h and time in hours. Uniformly accelerated motion adds the term ½·a·t². The acceleration calculator finds a = Δv/t. Kinetic energy is on another page, because this calculator has no mass field. A time of zero, a negative time, a negative distance, and a negative speed produce no result.
The unit switch in the header converts displayed meters to feet and m/s to ft/s, but the formula stays the same. The numbers in this text are SI reference values. With the header set to US units, 33.33 m/s is shown as 109.35 ft/s (74.6 mph). The number 120 in a field labeled m/s means 432.0 km/h, not 120 km/h, and not 120 mph. One hundred twenty kilometers per hour is entered as 33.33. The product 33.33 × 3.6 is 119.988 km/h, and the panel rounds that speed to 120.0 km/h. A time of 0 does not pass. A blank time field is not zero.
Further examples on this page: 4.00 m/s for 750 s gives 3,000.00 m. 9,000 m in 2,700 s gives 3.33 m/s (12.0 km/h). 22,000 m at 12.00 m/s gives 1,833.33 s (30.56 min). 250.00 m/s for 2,400 s gives 600,000.00 m. The button “Fill this example” enters those same numbers into the fields and refreshes the panel and the chart.
s = v · t
v = s / t and t = s / v
Model: uniform rectilinear motion (constant speed; Galileo’s definition in the Discorsi, 1638). The calculator reads exactly two fields and finds the third. It does not solve motion with acceleration.
Check: 33.33 m/s × 5,400 s = 179,982 m. The panel shows 179,982.00 m.
Uniform rectilinear motion is motion in which speed is constant in magnitude and direction. Every second adds the same number of meters. Instantaneous speed is v(t) = v, and the distance from time zero is s(t) = v·t. The SI unit of speed is the meter per second. In a school course the word “uniform” means the acceleration is zero. This calculator does not read an acceleration and does not add a term with the square of time.
The model describes a stretch at one steady speedometer reading, a conveyor in a textbook problem, and sound at one speed, provided v really does not change. It does not describe traffic lights, a jam, gear changes, or wind. Mass is not in the formula: at a given speed the distance does not depend on mass.
In Discorsi e dimostrazioni matematiche intorno a due nuove scienze (1638), on the third day, Galileo Galilei defined uniform motion as motion in which the moving body covers equal distances in any equal intervals of time. That is a definition of constant speed, not a separate discovery of a “miles formula.” The inclined-plane experiments and distance growing with the square of time belong to accelerated motion, and they live on another page.
The same relation is standard kinematics: OpenStax, College Physics 2e, section 2.3 “Time, Velocity, and Speed”; D. Halliday, R. Resnick, and J. Walker, Fundamentals of Physics, the chapter on motion in a straight line. When speed is constant, average speed equals instantaneous speed, so the quotient s/t is that same v.
Step 1. Constant v means the distance gained in time t is the product v·t, so s = v·t. Step 2. When s and t are known and t is greater than zero, v = s/t. Step 3. When s and v are known and v is greater than zero, t = s/v. Step 4. Distance check: 33.33 × 5,400 = 179,982, and the panel shows 179,982.00 m, with speed 33.33 m/s (120.0 km/h) and time 5,400.00 s (90.00 min). Step 5. Speed check: 240,000 / 4,320 = 55.555… The panel shows 55.56 m/s (200.0 km/h). Step 6. Time check: 480 / 8 = 60, and the panel shows 60.00 s (1.00 min).
The calculator always leaves exactly one field blank. Three numbers at once do not say which quantity to solve for. One number does not determine two unknowns. A blank field is not zero: rest requires 0 to be entered.
The calculator does not find acceleration, force, or energy. If you know two speeds and a time, open the acceleration calculator: a = Δv/t. When speed increases at a constant acceleration, open the uniformly accelerated motion calculator. When the only question is distance, and the speed is in km/h with the time in hours, open the distance calculator. When the trip includes stops, open average speed. Kinetic energy, ½mv², is on its own page.
The result is the length of the path at the entered speed, not a signed vector. A negative speed and a negative distance are rejected. A time of 0 and a negative time produce no result, because division by a zero time is not defined here, and a product at t = 0 does not stand in for a blank field.
33.33 m/s for 5,400 s gives 179,982.00 m, which is 179.982 km. That is the order of a highway problem for an hour and a half, not a reading off one speedometer. 6.00 m/s over 36,000 m gives 6,000.00 s, or 100.00 min. 8.00 m/s over 480 m gives one minute. 250.00 m/s for 2,400 s gives 600,000.00 m: that is the order of the speed of sound in a textbook problem, not a claim about one aircraft.
The definition and the derivation come from mechanics textbooks: OpenStax, College Physics 2e, section 2.3; D. Halliday, R. Resnick, and J. Walker, Fundamentals of Physics; H. D. Young and R. A. Freedman, University Physics, “Motion Along a Straight Line”; Galileo Galilei, Discorsi, 1638; BIPM, The International System of Units (SI), 9th edition (meter, second). This page is educational.
The calculator reads exactly two of the three fields and finds the third. For v = 33.33 m/s and t = 5,400 s the result is 179,982.00 m.
A constant 33.33 m/s for 5,400 s, which is 1.5 h. The missing quantity is distance.
s = 179,982.00 m
A stretch of 240,000 m covered in 4,320 s, which is 72.00 min. The missing quantity is speed.
v = 55.56 m/s (200.0 km/h)
A stretch of 36,000 m at a constant 6.00 m/s. The missing quantity is time.
t = 6,000.00 s (100.00 min)
A constant 8.00 m/s over 480 m. The missing quantity is time.
t = 60.00 s (1.00 min)
A stretch of 9,000 m covered in 2,700 s, which is 45.00 min. The missing quantity is speed.
v = 3.33 m/s (12.0 km/h)
A constant 4.00 m/s for 750 s, which is 12.50 min. The missing quantity is distance.
s = 3,000.00 m
A stretch of 22,000 m at a constant 12.00 m/s. The missing quantity is time.
t = 1,833.33 s (30.56 min)
A constant 250.00 m/s for 2,400 s, which is 40.00 min. The missing quantity is distance.
s = 600,000.00 m
The calculator finds the missing one of three quantities in uniform rectilinear motion: s = v·t, v = s/t, or t = s/v. Speed stays constant for the whole time. For 33.33 m/s and 5,400 s the distance is 179,982.00 m, and the panel describes that speed as 33.33 m/s (120.0 km/h) and that time as 5,400.00 s (90.00 min). The calculator does not find acceleration.
Enter speed in meters per second, distance in meters, and time in seconds. Enter 120 km/h as 33.33, because the panel then shows 120.0 km/h. One hour is 3,600 s, and 1.5 h is 5,400 s. The unit switch in the header converts the result to feet and ft/s, but seconds stay seconds. The number 120 in a field labeled m/s means 120 m/s, which is 432.0 km/h, not 120 km/h and not 120 mph.
The calculator requires exactly two numbers. The third field stays blank and is the unknown. A blank field does not mean zero. Three numbers at once, or only one, produce no result and a message appears. An entered 0 for speed, with a positive time and a blank distance, gives a distance of 0.00 m. An entered 0 for speed with a known positive distance does not give a time.
The distance calculator always finds s = v·t. It reads speed in kilometers per hour and time in hours, and the panel also shows pace. Here the unknown can be distance, speed, or time, and the fields are in meters per second, meters, and seconds. This calculator does not report pace.
Here the acceleration is zero, and the speed at the end of the interval equals the speed at the start. The uniformly accelerated motion calculator reads initial speed, acceleration, and time, and it finds distance from s = v₀·t + ½·a·t². One constant speed does not replace those three fields.
On the average speed page. This formula assumes one constant speed for the whole time you enter. A stop lowers the average and is not inside s = v·t, unless the number in the speed field is already the average for the whole trip and the time includes the stops.
The field label is meters per second. 120 in that field is 120 m/s, which is 432.0 km/h. One hundred twenty kilometers per hour is entered as 33.33. A comma and a period mean the same number, for example 33,33 and 33.33.
Multiply m/s by about 2.237. 33.33 m/s is about 74.6 mph, and in US units the panel shows 109.35 ft/s (74.6 mph). Multiply m/s by 3.6 for kilometers per hour: 33.33 × 3.6 is 119.988, which the metric panel rounds to 120.0 km/h. The other way, 60 mph is about 26.8 m/s.
A speed of 0 with a positive time and a blank distance gives a distance of 0.00 m, because the body is at rest. A distance of 0 with a positive time gives a speed of 0.00 m/s. Time at a speed of 0 and a positive distance is not finite, so the calculator shows a message and does not report a result. A time entered as 0 or as a negative number also produces no result. A negative distance and a negative speed are rejected.
Distance against time at the solved constant speed, at the instants 0.25 t, 0.5 t, t, 1.5 t, 2 t, and 3 t. At constant speed the chart is a straight line through the origin, and the slope matches the speed. The chart refreshes with the panel, including after an example is filled. When the speed is zero, the line is not drawn.
Multiply speed in m/s by time in seconds. For 33.33 m/s and 5,400 s: 33.33·5,400 = 179,982 m.
Divide distance by speed: t = s/v. At 36,000 m and 6 m/s the result is 6,000 s, or 100 min.
Divide by 3.6. 120 km/h is 33.33 m/s. Enter 33.33 in the field, not 120.
Here you can leave any one of v, s, or t blank. The distance companion only computes s = v·t with speed in km/h and time in hours.
Here v is constant on the whole segment. When the trip includes stops, use the average-speed calculator with total distance and total time.
The definition, history, and derivation below come from standard physics and metrology sources.
Page updated November 3, 2026.