Example 1
C = 1e-6 F, U = 12 V -> E = 7.2e-5 J.
Type C [F] and U [V]. The calculator computes E = ½ C U²: 1e-6 F at 12 V is 72 µJ, and 1e-4 F at 5 V is 1.25 mJ. Twice U is four times E.
Short alias: capacitor stored energy. Capacitance: C = Q/U.
Capacitance C (F) and Voltage U (V). The result shows up here.
Energy in a capacitor is E = ½ C U². At 1 µF (1e-6 F) and 12 V: E = 0.5 × 1e-6 × 144 = 7.2e-5 J = 72 µJ. At 100 µF and 5 V: E = 0.5 × 1e-4 × 25 = 1.25 mJ. U is squared: 24 V at 1 µF is 288 µJ, four times 12 V.
The form has two fields: C in farads and U in volts. The result is in joules. Type 1 µF as 1e-6, not as 1. A comma, a period, and 1e-6 mean the same C. 0.000001 also parses.
Typed 0 in C or U gives E = 0: no capacitance or no voltage. Both fields need a number before 72 µJ appears. A negative U is squared and gives the same E as |U|.
C = Q/U is on the neighbouring page. Here energy, there capacitance from charge and voltage. The short card of the same formula is stored energy: fewer examples, same result.
The joules are the same unit as in Ek = ½ m v². Different formula: C and U here, mass and speed there. Q = I t says where plate charge came from, not E.
Type 1e-6 and 12, click Calculate, and check 72 µJ. Then 24 V at the same C and see 288 µJ. The calculator computes ½ C U²; it does not charge the plates.
E = ½ · C · U2
Units: J, F, V.
The full page multiplies E = ½·C·U². 1e-6 F at 12 V is 72 µJ. 1e-4 F at 5 V is 1.25 mJ. Twice U is four times E.
C = 1e-6 F, U = 12 V -> E = 7.2e-5 J.
C = 1e-4 F, U = 5 V -> E = 1.25e-3 J.
Small C, high U: E ~ 12.4 J.
Typical filter capacitor.
C = 2.2e-5 F, U = 16 V.
High voltage, small C.
9 V battery, E = 2.03e-3 J.
Buffer capacitor.
Energy is 72 µJ. You compute ½ × 1e-6 × 144, which is 7.2×10⁻⁵ J, then write it in microjoules.
You get 1.25 mJ. Half times 1e-4 times 25 is 1.25×10⁻³ J, the millijoule from the second example.
Capacitance C [F], voltage U [V]. Result E [J]. Type 1 µF as 1e-6, not as 1.
U is squared. 24 V at 1 µF is 288 µJ, four times 72 µJ, not twice.
Here you compute energy from capacitance and voltage. There you solve for C from charge and voltage. Different unknown, same capacitor.
Yes. 0.000001, 0,000001 and 1e-6 are the same C [F]. 1e-6 is easier.
On capacitor stored energy. Same ½ C U² formula, shorter card, fewer examples.
Yes, result E [J] is the same joule as in Ek = ½ m v². Different formula: here C and U, there mass and speed.
Energy is 0 J. No capacitance or no voltage means an empty capacitor. Both fields still need a number.
You get 288 µJ. That is four times the 72 µJ from twelve volts, because U is squared.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.