Example 1
- Radius: 10
≈ 1256.64
What is the sphere surface area at r = 10? ≈ 1256.64.
Enter radius r (r > 0). The result is the sphere surface area S = 4πr² — the skin of the sphere, equal to four great-circle areas πr², not the interior volume. With r = 10 you get about 1256.64 in square units. Equivalently S = πd² with diameter d = 2r. Volume (4/3)πr³ lives on a sibling page.
Enter radius r (in). Surface area appears here.
S = 4πr². Volume is on the sphere volume calculator. A disk is on the circle area calculator.
Sphere surface area, written S (sometimes A), measures the “skin” of the sphere — the outer surface without the interior. The classical formula S = 4πr² says that skin equals four great-circle areas at the same radius r. A great circle is a cross-section through the centre; its area is πr², so 4·πr² = 4πr². This calculator takes a positive radius and returns S in cm² or in² according to the unit switch.
The calculator uses the number you enter in the Radius r field. It computes S = 4 × π × r² with the browser’s built-in π and shows two decimal places. At r = 10 the result is about 1256.64. At r = 5 the surface drops fourfold to about 314.16, because r is squared. A comma and a period in the field are equivalent.
The domain is r > 0. Zero and negative values do not describe a real sphere radius; a blank field is an error, not a surface of 0. Volume V = (4/3)πr³ lives on a sibling page — at r = 10 the interior is about 4188.79, not 1256.64. Cylinder lateral area 2πrh needs a height; a sphere in this formula has one parameter r. Diameter d = 2r must be halved first: diameter 10 means r = 5.
Historically, Archimedes in On the Sphere and Cylinder (about the 3rd century BCE) proved that the sphere’s surface equals the lateral area of the circumscribed cylinder. A cylinder of radius r and height equal to the diameter 2r has mantle 2πr·2r = 4πr². The method of exhaustion compares solids and surfaces without modern algebra; the result is the same formula this calculator uses. The basis is that classical result and standard handbooks.
Worked numbers on this page: r = 10 → S ≈ 1256.64; r = 1 → S ≈ 12.57; r = 5 → S ≈ 314.16; r = 2 → S ≈ 50.27; r = 3 → S ≈ 113.10; r = 4 → S ≈ 201.06; r = 6 → S ≈ 452.39; r = 8 → S ≈ 804.25. At r = 3 the digits 113.10 also appear in sphere volume — a coincidence of two formulas, not matching units. The result panel shows r, r², the 4πr² value, and great-circle area πr² as one quarter of the skin.
S = 4 × π × r², where r is the sphere radius.
Symbol S is surface area (the skin). Symbol r is the distance from centre to sphere. Constant π comes from circle geometry. Archimedes’ derivation: lateral area of the circumscribed cylinder 2πr·2r = 4πr².
Mathematical model: Archimedes’ sphere surface area (On the Sphere and Cylinder).
The surface area of a sphere of radius r is S = 4πr². Equivalently S = 4·A_disk, where A_disk = πr² is the area of a great circle — a cross-section through the centre. The symbol S (or A) denotes a surface measure in length-squared units. This calculator takes r > 0 from the form field and returns S with π.
A solid ball is the set of points at distance at most r from the centre; the sphere is the boundary. Surface area refers to that boundary; the classical result is 4πr².
In On the Sphere and Cylinder Archimedes proved that the sphere’s surface equals the lateral area of the circumscribed cylinder. That cylinder has base radius r and height equal to the diameter 2r; its mantle is a rectangle of sides 2πr and 2r, hence 4πr². He used the method of exhaustion: comparing surfaces and volumes by inscribed and circumscribed figures, without modern calculus.
The same treatise also gives V = (4/3)πr³ and the 2:3 ball-to-cylinder ratio. On CalcBoxer volume is a sibling page; here only S = 4πr².
Domain: r > 0. The map S(r) = 4πr² is strictly increasing and continuous on (0, ∞). Homogeneity: scaling lengths by λ > 0 scales area like λ². Halving the radius therefore quarters the skin (at r = 10 and r = 5: 1256.64 versus 314.16), while volume would drop eightfold.
Identities: S = 4πr² = πd² with d = 2r; r = √(S/(4π)); great-circle area A = S/4. The volume-to-surface ratio is V/S = r/3 for r > 0 — a geometric fact, not a separate output of this form.
Step 1 (great circle). A plane through the centre cuts a disk of area πr².
Step 2 (four disks). The school and classical statement S = 4πr² means four such disks.
Step 3 (circumscribed cylinder, Archimedes). Take a cylinder of radius r and height 2r in which the sphere is inscribed (touching the bases at the poles and the mantle at the equator). The lateral area is 2πr·2r = 4πr². Archimedes proved that mantle equals the sphere’s surface.
Step 4 (link to volume). Differentiating V = (4/3)πr³ with respect to r yields dV/dr = 4πr² = S — the “shell” of volume growth has surface measure. That is a modern view; Archimedes argued geometrically without derivatives.
For r = 1 (unit sphere) S = 4π ≈ 12.566371…. For d = 1 (unit diameter) r = 1/2 and S = π ≈ 3.141593…. The school approximation 4·3.14·r² is handy by hand but does not replace π here.
As r → 0, S → 0. A general ellipsoid is not 4πr². A hemisphere is 2πr² plus an optional base πr²; this form computes the full sphere 4πr².
The browser uses its built-in constant π. Multiplying 4·π·r² is stable for typical r. The display uses two decimal places.
Non-positive input is rejected. Comma and period are equivalent. The calculator does not guess diameter — enter r = d/2. The unit switch only relabels the square unit.
At r = 10 the result is S ≈ 1256.64 (with full-precision π and two decimal places). At r = 1: S ≈ 12.57. At r = 5: S ≈ 314.16 — exactly one quarter of the r = 10 value, because area scales like r². The panel also shows r², the factor 4π, and the great circle πr² = S/4 so the “four disks” link sits next to the result.
Sphere volume V = (4/3)πr³ is a separate model on a separate page. This form does not compute V, does not paint coat thickness, and does not convert diameter to radius automatically. If you know diameter d, enter r = d/2. The unit switch only changes the cm² / in² label — it does not convert the entered number.
Archimedes also compared the sphere with the circumscribed cylinder: with cylinder height 2r the lateral area 2πr·2r = 4πr² matches S. Hence the sibling cylinder-lateral page at h = 2r yields the same number for a different figure. Do not confuse surface with volume or with disk area πr².
Page examples use r = 10, 1, 5, 2, 3, 4, 6 and 8. Halving r quarters S; doubling r multiplies S by four. That quadratic scaling is the main classroom check against mixing surface with volume (which scales as r³).
Related models: sphere volume (4/3)πr³, disk area πr², circumference 2πr, cylinder lateral area 2πrh. For painting, S is a lower geometric estimate — roughness and coat thickness lie outside the model.
Sources: Archimedes, On the Sphere and Cylinder (Heath); MathWorld — Sphere; Wikipedia — Sphere; Wikipedia — On the Sphere and Cylinder; NIST DLMF (π). The calculator does not replace a geometry course or history of mathematics.
In school practice, confirm that r is the radius first, then compute 4πr². The hand sketch 3.14·4·r² is only a rough check — this page uses π. Educational tool.
S = 4πr². At r = 10 the surface is ≈ 1256.64. Domain: r > 0. Not volume.
≈ 1256.64
What is the sphere surface area at r = 10? ≈ 1256.64.
≈ 12.57
What is S at r = 1? ≈ 12.57.
≈ 314.16
What is S at r = 5? ≈ 314.16.
≈ 50.27
What is S at r = 2? ≈ 50.27.
≈ 113.10
What is S at r = 3? ≈ 113.10.
≈ 201.06
What is S at r = 4? ≈ 201.06.
≈ 452.39
What is S at r = 6? ≈ 452.39.
≈ 804.25
What is S at r = 8? ≈ 804.25.
S = 4πr², where r is the radius. That is four great-circle areas πr². At r = 10 the result is about 1256.64 square units. Volume (4/3)πr³ lives on a sibling page.
No. This page computes surface area S = 4πr² (the skin). Volume is (4/3)πr³. At r = 10 the surface is about 1256.64 and the volume about 4188.79 — different units and a different formula.
S = 4π·10² ≈ 1256.64 in square units (cm² or in² per the label). That is the first worked example and the same fill from “Fill this example”.
Because 4π·25 = 100π, and disk area πr² at r = 10 is also 100π. Same digits, different shapes: a sphere of radius 5 versus a disk of radius 10.
The form takes radius r. If you know diameter d, enter r = d/2. Diameter 10 means r = 5 and S ≈ 314.16; entering 10 as r gives ≈ 1256.64.
A radius describes a real sphere only for positive values. Zero gives no surface; a negative value is not a length. A blank field is an error, not a fake result of 0.
No. The unit switch only changes the cm² or in² label; it does not multiply the number you entered. Enter r in the same length unit you want for the result.
In On the Sphere and Cylinder Archimedes showed that the sphere’s surface equals the lateral area of the circumscribed cylinder: height 2r and circumference 2πr give 2πr·2r = 4πr².
Not exactly. The calculator uses the browser’s built-in π. At r = 1 the display is about 12.57 to two places.
The result is the area to cover. Coat thickness, number of layers, and waste sit outside S = 4πr². This page is only the geometric skin.
Use S = 4πr²: four times the great-circle area πr². With r = 10: 4π·100 ≈ 1256.64. From diameter: S = πd² with d = 2r.
About 615.75, because 4π·49 = 196π ≈ 615.75. Enter r = 7; the result is rounded to two decimal places.
No. Here only the full sphere S = 4πr². Volume (4/3)πr³ and hemisphere surface (2πr² plus an optional πr² base) are not on this card.
r = √(S/(4π)). With S ≈ 1256.64: S/(4π) ≈ 100, so r ≈ 10. The form takes r and returns S, not the inverse.
Diameter 6 m means r = 3 m, so S = 4π·9 = 36π ≈ 113.10 m². Same as S = πd². Coat thickness and waste sit outside the formula.
The formula S = 4πr², Archimedes’ result, and the historical note below come from recognized sources.
Page Updated November 2, 2026.