Cylinder lateral area calculator

Enter the base radius r and the height h (both greater than zero). The result is the lateral area of a right circular cylinder Sb = 2πrh — the side wall without the bottom or the lid, equal to the rectangle C×h with C = 2πr. With r = 5 and h = 12 you get 376.99 (that is 120π to two decimal places). This is not volume πr²h and not the total surface Pc = 2πr(h+r).

Input data

Result

Enter radius r and height h greater than zero.

Domain: r > 0 and h > 0 in the same length unit. This is not volume πr²h and not Atot = 2πr(h+r). The result uses two decimal places.

How it works

How Sb is computed at r = 5 and h = 12
r5
h12
C = 2πr31.42
Sb376.99

A right circular cylinder has two parallel circular bases of equal radius r and a lateral surface that, when cut along a generator, unrolls into a rectangle. One side of that rectangle equals the base circumference C = 2πr; the other side is the height h. The area of the rectangle — the lateral area — is therefore Sb = C·h = 2πrh. This calculator computes exactly that quantity: the side wall without the bottom and without the lid.

The domain is simple: r > 0 and h > 0. Zero or a negative value does not describe a positive lateral area here — the calculator shows a message instead of inventing a result. An empty field leaves the result blank. Commas and periods in the fields are equivalent. The unit switch only changes unit labels on the result (cm/cm² or in/in²); it does not multiply or divide the numbers you enter.

The calculator uses the numbers you enter: base radius r and height h. The calculator computes Sb = 2·π·r·h with π and rounds to two decimal places. It also shows the entered r and h, the circumference C = 2πr, and the C·h check. At r = 5 and h = 12 you get Sb = 120π ≈ 376.99. At r = 1 and h = 1 the wrap is 2π ≈ 6.28. The pairs r = 10, h = 2 and r = 2, h = 10 both give 125.66, because only the product r·h matters.

In practice the lateral area matches a can label, sheet metal for a pipe, or paint on a cylindrical wall — without lids. If you need a closed can, add 2πr² separately. A cone uses slant height l, not cylinder height: its lateral area is πrl. A sphere uses 4πr² and has no h. Cylinder volume πr²h lives on a separate page.

Historically, Archimedes in On the Sphere and Cylinder showed that the surface area of a sphere equals the lateral area of the circumscribed cylinder (cylinder height 2r, circumference 2πr, so Sb = 2πr·2r = 4πr²). That is context for solids of revolution, not a separate form formula. The formula Sb = 2πrh belongs to standard solid geometry (including MathWorld — Cylinder and Wikipedia — Lateral surface).

The neighbouring cylinder volume page computes πr²h. Volume from circumference starts from C instead of r. Here the first field is always the radius, and the result is always lateral area — never volume and never total surface.

Formula

Sb = 2 × π × r × h, equivalently Sb = C · h with C = 2πr.

Symbol r is the radius of the circular base (form field). Symbol h is the cylinder height. The constant π comes from circle geometry. Domain: r > 0, h > 0.

Mathematical model: right circular cylinder lateral surface area as the area of the rectangle obtained by unrolling the wall. Sources: standard solid geometry; MathWorld — Cylinder; Wikipedia — Lateral surface; Archimedes’ On the Sphere and Cylinder as historical context (sphere area equals lateral area of the circumscribed cylinder).

Step-by-step derivation

Definition

The lateral area of a right circular cylinder is the measure of the side wall without the bases. After cutting the cylinder along a generator and unrolling it onto a plane you obtain a rectangle with sides C = 2πr (the circumference of the circular base) and h (the height measured perpendicularly between the bases). The area of that rectangle is Sb = C·h = 2πrh. Units must be consistent: if r and h are in inches, the result is in square inches.

A right circular cylinder has bases that are disks of equal radius, and generators perpendicular to the base planes. The formula Sb = 2πrh does not count the bottom or the lid — those two disks have total area 2πr². The total surface of a closed cylinder is Atot = 2πr² + 2πrh = 2πr(h+r). This calculator returns Sb only.

Historical and conceptual context

Lateral-surface geometry belongs to classical solid geometry. Archimedes in On the Sphere and Cylinder (Περὶ σφαίρας καὶ κυλίνδρου) showed among other results that the surface area of a sphere equals the lateral area of the circumscribed cylinder: with cylinder height 2r and circumference 2πr you get Sb = 4πr², exactly the sphere area. Euclid in the Elements (Book XII) treats cylinders by exhaustion, comparing solids of equal height.

Conceptually the net is the key school and engineering picture: a can label, a sheet-metal blank for a pipe, or the heat-exchange surface on the outside of a cylinder. The calculator does not guess material or paint thickness — it computes only the geometric area of an ideal lateral surface. When the cross-section is not a circle or the height is not constant, 2πrh no longer applies.

Formal properties

Input domain: r > 0, h > 0 (in numerical practice also finite floating-point numbers). For r ≤ 0 or h ≤ 0 the lateral area is not positive as a solid. Homogeneity: Sb scales linearly with r and linearly with h. If every length is multiplied by λ > 0, then r′ = λr, h′ = λh and Sb′ = λ²Sb, matching the dimension of area.

Equivalent forms: Sb = 2πrh = C·h = πdh, where C = 2πr and d = 2r. At fixed r the map Sb(h) is linear; at fixed h the map Sb(r) is linear too. Relative sensitivity: ∂Sb/Sb = ∂r/r + ∂h/h, so relative errors in radius and height enter with weight 1 (unlike volume, where the radius error has weight 2).

Full derivation from the net

Step 1. The circumference of a circle of radius r is C = 2πr. That is the definition of π as the ratio of circumference to diameter (C/d = π).

Step 2. Cut the lateral surface along a generator and unroll it onto the plane. You obtain a rectangle of width C and height h.

Step 3. Rectangle area: Sb = C·h = 2πr·h = 2πrh. Equivalently Sb = πdh with d = 2r.

Step 4 (consistency check). The panel shows C = 2πr and the product C·h; it must match 2πrh. At r = 5, h = 12: C ≈ 31.42 and C·h ≈ 376.99 = 2π·5·12.

Special cases

When r = 1 and h = 1, Sb = 2π ≈ 6.28. When r = h, Sb = 2πr² — numerically equal to the area of one circle of radius r√2, but that is only a numerical coincidence. For the cylinder circumscribed about a sphere of radius R (h = 2R, r = R) the lateral area is 4πR² and equals the sphere area — Archimedes’ classic result. The pairs (r, h) and (h, r) give the same Sb only when the product matches; swapping r↔h is not a geometric identity of the cylinder, only algebra of the product.

The limit h → 0 yields Sb → 0 (a flattened band). The limit r → 0 at fixed h also yields Sb → 0. An oblique cylinder with a circular base has a lateral area that depends on the slant generator, not on perpendicular height alone — this calculator assumes a right cylinder.

Numerical and computational notes

The calculator uses π in floating-point arithmetic and rounds the result to two decimal places, matching the examples on the page. For very large 2πrh a floating-point arithmetic overflow is possible; for typical user dimensions the result fits safely. The order 2·π·r·h is algebraically equivalent to C·h.

Commas and periods in the fields are equivalent. The calculator does not model a cone, an oblique cylinder, label overlap, or paint thickness. A diameter entered as r doubles the result — always divide diameter by two before entering.

In lab and school work it helps to distinguish the outer surface from the inner surface of a pipe with wall thickness δ: a tape on the outside measures C_out = 2π(R+δ), while the inner wall has C_in = 2πR. Substituting the outer r into 2πrh overstates the inner area. The fix is to use the appropriate radius. The formula ignores meniscus, welds, and conical tank heads.

Related ideas and sources

Related models on this site: cylinder volume (πr²h), cylinder volume from circumference, circle circumference (C = 2πr), circle area (πr²), and sphere surface area (4πr²). This formula does not compute volume or the closed total surface with lids.

Sources: Archimedes, On the Sphere and Cylinder (Heath, The Works of Archimedes); MathWorld — Cylinder; Wikipedia — Cylinder (geometry); Wikipedia — Lateral surface; NIST DLMF (π). The calculator is an educational tool and does not replace an engineering standard for pressure vessels.

How to use

  1. Enter the base radius r, for example 5, in the Radius r field.
  2. Enter the height h, for example 12.
  3. Click Calculate or wait for the live result. r = 5 and h = 12 give 376.99.
  4. Check the panel: r, h, circumference 2πr, and the C·h check. The cylinder-and-net diagram refreshes with the inputs.
  5. r ≤ 0 or h ≤ 0 does not pass. Volume lives on the cylinder volume page; add lids separately for total surface.

Symbol glossary

Cylinder lateral area: Sb = 2πrh. At r = 5 and h = 12 the result is 376.99.

r
Radius of the circular base in the first field. Must be greater than zero. At r = 5 and h = 12, Sb = 376.99.
h
Cylinder height in the second field. Same length unit as r. h > 0.
C
Base circumference C = 2πr. At r = 5 it is about 31.42. Sb = C·h.
Sb
Lateral area 2πrh. At r = 5 and h = 12 it is 376.99 to two places.
π
Circle constant from π in the browser. It sits in the product 2πrh.

Examples

Example 1

  • r: 5 · h: 12

376.99

What lateral area at r = 5 and h = 12? 376.99.

Example 2

  • r: 1 · h: 1

6.28

What is Sb at r = 1 and h = 1? 6.28.

Example 3

  • r: 10 · h: 2

125.66

What is Sb at r = 10 and h = 2? 125.66.

Example 4

  • r: 3 · h: 8

150.80

What is Sb at r = 3 and h = 8? 150.80.

Example 5

  • r: 4 · h: 4

100.53

What is Sb at r = h = 4? 100.53.

Example 6

  • r: 2 · h: 10

125.66

What is Sb at r = 2 and h = 10? 125.66.

Example 7

  • r: 7 · h: 3

131.95

What is Sb at r = 7 and h = 3? 131.95.

Example 8

  • r: 6 · h: 6

226.19

What is Sb at r = h = 6? 226.19.

Related calculators

Common questions

What is the domain for r and h?

Base radius r and height h must both be greater than zero. The calculator rejects zero and negative values — they do not define a positive lateral area of a right circular cylinder in this model. An empty field leaves the result blank, not zero.

What is the lateral area at r = 5 and h = 12?

The result is 376.99. That is 120π to two decimal places: 2π·5·12 = 120π. The same figure appears in example 1 and in the press-seed paragraph. The C·h check with C = 2πr returns the same number.

Where does Sb = 2πrh come from?

The lateral surface of a right circular cylinder unrolls to a rectangle whose sides are the base circumference C = 2πr and the height h. Hence Sb = C·h = 2πrh. This is not volume πr²h and not the closed total surface with lids.

Is this the full cylinder surface?

No. This page computes the side only. The total surface of a closed cylinder is 2πr² + 2πrh = 2πr(h+r). At r = 5 and h = 12 the full surface is 534.07, while the side alone is 376.99.

Is this cylinder volume?

No. Volume is πr²h (cm³ or in³). Lateral area is in cm² or in². At r = 5 and h = 12 the volume is about 942.48 — a different unit on another page.

How do I turn this into a can label?

The result is the wrap area. The label rectangle has sides 2πr and h. At r = 5 the sheet width is about 31.42 and the sheet height is h = 12. Glue overlap sits outside the formula.

Is diameter 10 the same as r = 10?

No. Diameter 10 means r = 5. If you enter 10 as r, the result doubles, because in Sb = 2πrh the radius appears to the first power.

Which units does the result use?

Radius and height must share one length unit. With Metric the labels are cm and cm²; with US they are in and in². The header switch changes labels only — it does not convert the numbers you entered.

Do the currency and unit settings in the page header affect the result?

No. The currency and unit settings in the page header do not affect this result. Only r, h and π matter.

Does a comma in 2.5 work?

Yes. 2.5 and 2,5 are the same radius. Spaces inside a number are ignored.

Why do r = 10, h = 2 and r = 2, h = 10 give the same result?

Because Sb = 2πrh depends on the product r·h. 10·2 and 2·10 are the same 20, so 2π·20 ≈ 125.66 in both cases.

Why is Archimedes listed in the sources?

In On the Sphere and Cylinder Archimedes showed that the surface area of a sphere equals the lateral area of the circumscribed cylinder (height 2r, circumference 2πr). This calculator computes Sb = 2πrh for any h — the citation is historical context, not a separate form formula.

How do I calculate the lateral area of a cylinder?

Use Sb = 2πrh: multiply the base circumference C = 2πr by the height h. With r = 5 and h = 12: 2π·5·12 = 120π ≈ 376.99. The result is rounded to two decimal places.

What is the lateral area at r = 3 and h = 10?

About 188.50, because 2π·3·10 = 60π. That is a classic textbook example; enter r = 3 and h = 10.

Does the calculator compute total surface area or volume?

No. Here only Sb = 2πrh (the side wall). Total surface Pc = 2πr(h+r) and volume V = πr²h live on other pages — they are not on this card.

How do I get Sb from diameter d?

First take r = d/2, then Sb = 2πrh = πdh. With diameter 10 and h = 12: r = 5, so Sb ≈ 376.99. Do not enter d as r.

Does the result include label overlap or wall thickness?

No. The result is the ideal geometric area 2πrh. Glue overlap, paint, and outer-versus-inner radius differences sit outside the formula.

At r = 5 and h = 12 the lateral area is 376.99 (120π). The C·h check returns the same number. Volume πr²h is on the cylinder volume page.

Knowledge sources

The formula, derivation, and historical context below come from established geometry references.

Page Updated November 2, 2026.