Example 1
- r: 5 · h: 12
376.99
What lateral area at r = 5 and h = 12? 376.99.
Enter the base radius r and the height h (both greater than zero). The result is the lateral area of a right circular cylinder Sb = 2πrh — the side wall without the bottom or the lid, equal to the rectangle C×h with C = 2πr. With r = 5 and h = 12 you get 376.99 (that is 120π to two decimal places). This is not volume πr²h and not the total surface Pc = 2πr(h+r).
Enter radius r and height h greater than zero.
Domain: r > 0 and h > 0 in the same length unit. This is not volume πr²h and not Atot = 2πr(h+r). The result uses two decimal places.
A right circular cylinder has two parallel circular bases of equal radius r and a lateral surface that, when cut along a generator, unrolls into a rectangle. One side of that rectangle equals the base circumference C = 2πr; the other side is the height h. The area of the rectangle — the lateral area — is therefore Sb = C·h = 2πrh. This calculator computes exactly that quantity: the side wall without the bottom and without the lid.
The domain is simple: r > 0 and h > 0. Zero or a negative value does not describe a positive lateral area here — the calculator shows a message instead of inventing a result. An empty field leaves the result blank. Commas and periods in the fields are equivalent. The unit switch only changes unit labels on the result (cm/cm² or in/in²); it does not multiply or divide the numbers you enter.
The calculator uses the numbers you enter: base radius r and height h. The calculator computes Sb = 2·π·r·h with π and rounds to two decimal places. It also shows the entered r and h, the circumference C = 2πr, and the C·h check. At r = 5 and h = 12 you get Sb = 120π ≈ 376.99. At r = 1 and h = 1 the wrap is 2π ≈ 6.28. The pairs r = 10, h = 2 and r = 2, h = 10 both give 125.66, because only the product r·h matters.
In practice the lateral area matches a can label, sheet metal for a pipe, or paint on a cylindrical wall — without lids. If you need a closed can, add 2πr² separately. A cone uses slant height l, not cylinder height: its lateral area is πrl. A sphere uses 4πr² and has no h. Cylinder volume πr²h lives on a separate page.
Historically, Archimedes in On the Sphere and Cylinder showed that the surface area of a sphere equals the lateral area of the circumscribed cylinder (cylinder height 2r, circumference 2πr, so Sb = 2πr·2r = 4πr²). That is context for solids of revolution, not a separate form formula. The formula Sb = 2πrh belongs to standard solid geometry (including MathWorld — Cylinder and Wikipedia — Lateral surface).
The neighbouring cylinder volume page computes πr²h. Volume from circumference starts from C instead of r. Here the first field is always the radius, and the result is always lateral area — never volume and never total surface.
Sb = 2 × π × r × h, equivalently Sb = C · h with C = 2πr.
Symbol r is the radius of the circular base (form field). Symbol h is the cylinder height. The constant π comes from circle geometry. Domain: r > 0, h > 0.
Mathematical model: right circular cylinder lateral surface area as the area of the rectangle obtained by unrolling the wall. Sources: standard solid geometry; MathWorld — Cylinder; Wikipedia — Lateral surface; Archimedes’ On the Sphere and Cylinder as historical context (sphere area equals lateral area of the circumscribed cylinder).
The lateral area of a right circular cylinder is the measure of the side wall without the bases. After cutting the cylinder along a generator and unrolling it onto a plane you obtain a rectangle with sides C = 2πr (the circumference of the circular base) and h (the height measured perpendicularly between the bases). The area of that rectangle is Sb = C·h = 2πrh. Units must be consistent: if r and h are in inches, the result is in square inches.
A right circular cylinder has bases that are disks of equal radius, and generators perpendicular to the base planes. The formula Sb = 2πrh does not count the bottom or the lid — those two disks have total area 2πr². The total surface of a closed cylinder is Atot = 2πr² + 2πrh = 2πr(h+r). This calculator returns Sb only.
Lateral-surface geometry belongs to classical solid geometry. Archimedes in On the Sphere and Cylinder (Περὶ σφαίρας καὶ κυλίνδρου) showed among other results that the surface area of a sphere equals the lateral area of the circumscribed cylinder: with cylinder height 2r and circumference 2πr you get Sb = 4πr², exactly the sphere area. Euclid in the Elements (Book XII) treats cylinders by exhaustion, comparing solids of equal height.
Conceptually the net is the key school and engineering picture: a can label, a sheet-metal blank for a pipe, or the heat-exchange surface on the outside of a cylinder. The calculator does not guess material or paint thickness — it computes only the geometric area of an ideal lateral surface. When the cross-section is not a circle or the height is not constant, 2πrh no longer applies.
Input domain: r > 0, h > 0 (in numerical practice also finite floating-point numbers). For r ≤ 0 or h ≤ 0 the lateral area is not positive as a solid. Homogeneity: Sb scales linearly with r and linearly with h. If every length is multiplied by λ > 0, then r′ = λr, h′ = λh and Sb′ = λ²Sb, matching the dimension of area.
Equivalent forms: Sb = 2πrh = C·h = πdh, where C = 2πr and d = 2r. At fixed r the map Sb(h) is linear; at fixed h the map Sb(r) is linear too. Relative sensitivity: ∂Sb/Sb = ∂r/r + ∂h/h, so relative errors in radius and height enter with weight 1 (unlike volume, where the radius error has weight 2).
Step 1. The circumference of a circle of radius r is C = 2πr. That is the definition of π as the ratio of circumference to diameter (C/d = π).
Step 2. Cut the lateral surface along a generator and unroll it onto the plane. You obtain a rectangle of width C and height h.
Step 3. Rectangle area: Sb = C·h = 2πr·h = 2πrh. Equivalently Sb = πdh with d = 2r.
Step 4 (consistency check). The panel shows C = 2πr and the product C·h; it must match 2πrh. At r = 5, h = 12: C ≈ 31.42 and C·h ≈ 376.99 = 2π·5·12.
When r = 1 and h = 1, Sb = 2π ≈ 6.28. When r = h, Sb = 2πr² — numerically equal to the area of one circle of radius r√2, but that is only a numerical coincidence. For the cylinder circumscribed about a sphere of radius R (h = 2R, r = R) the lateral area is 4πR² and equals the sphere area — Archimedes’ classic result. The pairs (r, h) and (h, r) give the same Sb only when the product matches; swapping r↔h is not a geometric identity of the cylinder, only algebra of the product.
The limit h → 0 yields Sb → 0 (a flattened band). The limit r → 0 at fixed h also yields Sb → 0. An oblique cylinder with a circular base has a lateral area that depends on the slant generator, not on perpendicular height alone — this calculator assumes a right cylinder.
The calculator uses π in floating-point arithmetic and rounds the result to two decimal places, matching the examples on the page. For very large 2πrh a floating-point arithmetic overflow is possible; for typical user dimensions the result fits safely. The order 2·π·r·h is algebraically equivalent to C·h.
Commas and periods in the fields are equivalent. The calculator does not model a cone, an oblique cylinder, label overlap, or paint thickness. A diameter entered as r doubles the result — always divide diameter by two before entering.
In lab and school work it helps to distinguish the outer surface from the inner surface of a pipe with wall thickness δ: a tape on the outside measures C_out = 2π(R+δ), while the inner wall has C_in = 2πR. Substituting the outer r into 2πrh overstates the inner area. The fix is to use the appropriate radius. The formula ignores meniscus, welds, and conical tank heads.
Related models on this site: cylinder volume (πr²h), cylinder volume from circumference, circle circumference (C = 2πr), circle area (πr²), and sphere surface area (4πr²). This formula does not compute volume or the closed total surface with lids.
Sources: Archimedes, On the Sphere and Cylinder (Heath, The Works of Archimedes); MathWorld — Cylinder; Wikipedia — Cylinder (geometry); Wikipedia — Lateral surface; NIST DLMF (π). The calculator is an educational tool and does not replace an engineering standard for pressure vessels.
Cylinder lateral area: Sb = 2πrh. At r = 5 and h = 12 the result is 376.99.
376.99
What lateral area at r = 5 and h = 12? 376.99.
6.28
What is Sb at r = 1 and h = 1? 6.28.
125.66
What is Sb at r = 10 and h = 2? 125.66.
150.80
What is Sb at r = 3 and h = 8? 150.80.
100.53
What is Sb at r = h = 4? 100.53.
125.66
What is Sb at r = 2 and h = 10? 125.66.
131.95
What is Sb at r = 7 and h = 3? 131.95.
226.19
What is Sb at r = h = 6? 226.19.
Base radius r and height h must both be greater than zero. The calculator rejects zero and negative values — they do not define a positive lateral area of a right circular cylinder in this model. An empty field leaves the result blank, not zero.
The result is 376.99. That is 120π to two decimal places: 2π·5·12 = 120π. The same figure appears in example 1 and in the press-seed paragraph. The C·h check with C = 2πr returns the same number.
The lateral surface of a right circular cylinder unrolls to a rectangle whose sides are the base circumference C = 2πr and the height h. Hence Sb = C·h = 2πrh. This is not volume πr²h and not the closed total surface with lids.
No. This page computes the side only. The total surface of a closed cylinder is 2πr² + 2πrh = 2πr(h+r). At r = 5 and h = 12 the full surface is 534.07, while the side alone is 376.99.
No. Volume is πr²h (cm³ or in³). Lateral area is in cm² or in². At r = 5 and h = 12 the volume is about 942.48 — a different unit on another page.
The result is the wrap area. The label rectangle has sides 2πr and h. At r = 5 the sheet width is about 31.42 and the sheet height is h = 12. Glue overlap sits outside the formula.
No. Diameter 10 means r = 5. If you enter 10 as r, the result doubles, because in Sb = 2πrh the radius appears to the first power.
Radius and height must share one length unit. With Metric the labels are cm and cm²; with US they are in and in². The header switch changes labels only — it does not convert the numbers you entered.
No. The currency and unit settings in the page header do not affect this result. Only r, h and π matter.
Yes. 2.5 and 2,5 are the same radius. Spaces inside a number are ignored.
Because Sb = 2πrh depends on the product r·h. 10·2 and 2·10 are the same 20, so 2π·20 ≈ 125.66 in both cases.
In On the Sphere and Cylinder Archimedes showed that the surface area of a sphere equals the lateral area of the circumscribed cylinder (height 2r, circumference 2πr). This calculator computes Sb = 2πrh for any h — the citation is historical context, not a separate form formula.
Use Sb = 2πrh: multiply the base circumference C = 2πr by the height h. With r = 5 and h = 12: 2π·5·12 = 120π ≈ 376.99. The result is rounded to two decimal places.
About 188.50, because 2π·3·10 = 60π. That is a classic textbook example; enter r = 3 and h = 10.
No. Here only Sb = 2πrh (the side wall). Total surface Pc = 2πr(h+r) and volume V = πr²h live on other pages — they are not on this card.
First take r = d/2, then Sb = 2πrh = πdh. With diameter 10 and h = 12: r = 5, so Sb ≈ 376.99. Do not enter d as r.
No. The result is the ideal geometric area 2πrh. Glue overlap, paint, and outer-versus-inner radius differences sit outside the formula.
The formula, derivation, and historical context below come from established geometry references.
Page Updated November 2, 2026.