Example 1
- Radius r: 10
≈ 314.16
What area at r = 10? ≈ 314.16; circumference ≈ 62.83.
Enter radius r. The calculator computes area A = πr². At r = 10 the result is about 314.16 square units; at r = 5 about 78.54. The form takes radius, not diameter — for diameter 20 divide by 2 first.
Enter radius r (in). Area appears here.
A = πr². Circumference C = 2πr is on the circumference calculator. Sphere surface 4πr² has its own calculator.
Circle area (disk area), written A, measures the region inside the circumference including the boundary. The classical formula A = πr² multiplies the constant π by the square of the radius. Because circumference satisfies C = 2πr, equivalently A = ½·r·C — the identity Archimedes proved in Measurement of a Circle. Both writings describe the same Euclidean geometric model, not a “school approximation.”
The calculator uses the number you enter in the radius field r. It computes r², then A = πr², and shows the companion circumference C = 2πr beside it. For r = 10 the area is about 314.16 square units. Comma and period in the field are equivalent.
The domain is r > 0. Zero and negative values do not describe a real disk area; a blank field is an error, not area 0. The form does not take diameter as a direct input: diameter 20 means r = 10. If you enter 20 as r, then r² = 400 and the area comes out four times too large. Sphere surface 4πr² and an annulus are separate models.
Historically Archimedes proved that the area of a circle equals the area of a right triangle whose legs equal the radius and the circumference. Hence A = ½rC; substituting C = 2πr yields A = πr². He also bounded the ratio C/d with regular 96-gons: 3 10/71 < π < 3 1/7. Modern π is a transcendental constant; NIST lists it among mathematical constants, and the JS engine uses Math.PI.
Numeric examples on this page: r = 10 → A ≈ 314.16; r = 1 → A ≈ 3.14; r = 5 → A ≈ 78.54; r = 2 → A ≈ 12.57; r = 7 → A ≈ 153.94; r = 0.5 → A ≈ 0.79; r = 12 → A ≈ 452.39; r = 3 → A ≈ 28.27. The Pythagorean theorem does not compute this area: there are no sides a and b, only one radius. The result is area, not an angle in radians.
A = π × r² and equivalently A = ½ × r × C, where C = 2πr.
Symbol A is disk area. Symbol r is the radius — distance from center to the circle. Constant π enters through the circumference definition. Archimedes’ derivation: A = ½rC; substituting C = 2πr yields A = πr².
Mathematical model: classical circle-area formula (Euclidean geometry), with Archimedes’ identity A = ½rC in Measurement of a Circle.
The area of a circle (disk) of radius r is A = πr². Equivalently, with circumference C = 2πr, A = ½·r·C. The constant π is the ratio of circumference to diameter in Euclidean plane geometry. This calculator takes a positive radius r and returns A under that definition, together with the steps r² and πr².
A circle is the set of points at fixed distance r from a center; a disk is the interior including the boundary. Area is the two-dimensional measure of that region. In analysis the disk area follows from the double integral over x²+y² ≤ r² or from ∫₋ᵣʳ 2√(r²−x²) dx = 4∫₀ʳ √(r²−x²) dx, which equals exactly πr².
In Measurement of a Circle Archimedes proved that the area of a circle equals the area of a right triangle with legs r and C. Hence, A = ½rC = πr² after using C = 2πr. In the same treatise he bounded π with inscribed and circumscribed regular polygons; for 96-gons he obtained 223/71 < π < 22/7. Euclid’s Elements (Books III and XII) develop circle theory and similarity without the modern symbol π.
Later approximations (Liu Hui, Zu Chongzhi, Madhava–Leibniz series, Machin) tightened bounds on π. Conceptually A = πr² is not a school shortcut — it is the Euclidean measure of the disk given the constant π. On a sphere or in hyperbolic geometry, analogous “circle area” formulas differ from πr².
Domain: r > 0. The map A(r) = πr² is strictly increasing and convex for r > 0. Homogeneity: scaling lengths by λ > 0 scales area like λ². Link to circumference: A = C²/(4π), so knowing C determines area without a separate radius measurement.
Identities: A = πr² = ½rC = C²/(4π); r = √(A/π); C = 2√(πA). A sector with central angle θ in radians has area (θ/(2π))·A = ½r²θ. A full turn θ = 2π recovers A.
Isoperimetry in the plane: among closed curves of fixed circumference, the circle maximizes area (the isoperimetric theorem). Thus, for fixed C the disk has the largest A among simple plane regions with that boundary.
Step 1 (integral). Let the disk be x²+y² ≤ r². In polar coordinates: ∫₀^{2π}∫₀ʳ ρ dρ dφ = 2π·(r²/2) = πr².
Step 2 (Archimedes). Circle area equals the triangle with legs r and C. The argument uses exhaustion by polygons: an inscribed regular polygon has area less than A, a circumscribed one greater, and the limit yields A = ½rC.
Step 3 (substitution). From C = 2πr you get ½rC = πr². The identity is exact in Euclidean geometry, not an approximation.
Step 4 (the square). A common error is confusing A = πr² with A = πr. At r = 10 the gap between 314.16 and 31.42 is an order of ten; the cause is omitting the square.
For r = 1 (unit circle) A = π ≈ 3.141592…. For r = 10, A = 100π ≈ 314.159…. School approximations A ≈ 3.14·r² or (22/7)·r² help hand calculation but are not the exact value of π.
As r → 0, A → 0. An ellipse with semi-axes a, b has area πab and reduces to πr² only when a = b = r. An annulus with radii R > r has area π(R²−r²); this calculator covers only the full disk.
The browser uses π (about 15–17 significant digits in floating-point arithmetic). For typical user radii the π rounding error is negligible next to measurement error. Multiplying π·r·r is numerically stable; cancellation of nearby quantities is avoided.
The code evaluates A = π · r · r and the companion circumference C = 2 · π · r. At r = 5, r² = 25 and A = 25π ≈ 78.54; at r = 10, A = 100π ≈ 314.16. Those values fill the examples and the disk diagram. π comes from π (floating-point arithmetic), not from a hand-entered 3.14.
Non-positive input is rejected. Comma and period are equivalent. The calculator does not return sector or annulus area — those models live on separate pages when available.
Link to a cylinder: knowing A = πr² and height h gives volume V = A·h = πr²h. Relative error in r passes into A with weight 2 because r² appears.
Practical approximations: 22/7 overestimates π by about 0.04%; 355/113 is accurate to six places. The calculator does not switch to fractions — it uses the browser’s built-in floating-point constant.
Related models: circumference, sector area, annulus, sphere surface 4πr², cylinder volume from base πr². Disk area alone does not locate the center in the plane.
Do not enter the diameter as r — divide by 2 first. Sphere surface area 4πr² and circular sector or segment area are separate models. Archimedes’ identity A = ½·r·C ties area to circumference at the same r; the panel reports both quantities, but the primary result remains A = πr².
Sources: Archimedes, Measurement of a Circle (Heath); Euclid, Elements, Books III and XII; NIST Mathematical Constants (π); MathWorld — Circle, Disk; Wikipedia — Area of a circle; Wikipedia — Measurement of a Circle. The calculator does not replace a course in analysis or history of mathematics.
A = πr² = ½rC. At r = 10, area ≈ 314.16. Domain: r > 0.
≈ 314.16
What area at r = 10? ≈ 314.16; circumference ≈ 62.83.
≈ 3.14
What is the area at r = 1? π ≈ 3.14 (not 2π).
≈ 78.54
What area at r = 5? 25π ≈ 78.54.
≈ 12.57
What is the area at r = 2? 4π ≈ 12.57.
≈ 153.94
What area at r = 7? 49π ≈ 153.94.
≈ 0.79
What is the area at r = 0.5? 0.25π ≈ 0.79.
≈ 452.39
What area at r = 12? 144π ≈ 452.39.
≈ 28.27
What is the area at r = 3? 9π ≈ 28.27.
Area A = πr² measures the disk. Circumference C = 2πr is rim length. At r = 10 the area is about 314.16 square units and the circumference about 62.83. Full circumference lives on its own calculator.
Because area is π times r squared. Ten squared is one hundred; 100 × π ≈ 314.16. Multiplying r alone by π yields about 31.4 and is not the area formula.
Not directly. The form expects radius r. Diameter 20 means r = 10. If you enter 20 as r, the result is four times too large because r² grows quadratically.
Radius describes a real circle only for positive values. Zero is not a disk area; a negative length is not a length. A blank field is an error, not area 0.
A = π·10² ≈ 314.16 in square units matching r. That is the first example on this page. Circumference from the same r is about 62.83.
Yes. Archimedes proved that the circle’s area equals a right triangle with legs r and C. Because C = 2πr, you get ½·r·C = πr². The result panel shows A = πr² plus r and r².
No. The unit switch only changes the cm or in label (and cm²/in²); it does not multiply the entered digits. If you measured 10 cm and want inches, convert the length yourself first.
In Measurement of a Circle he proved the disk area equals a right triangle with legs r and C, so A = ½rC = πr². He also bounded π with 96-gons. Here the result uses the built-in constant π.
No. Sphere surface is 4πr² and has its own calculator. At r = 10 it is about 1256.64 square units, not 314.16 of a flat disk.
No. Area is in in² or cm². Radians measure angles — they belong on the degrees-and-radians page, not here.
Square the radius and multiply by π. At r = 10: 10² = 100, A = 100π ≈ 314.16. At r = 5: 25π ≈ 78.54. At r = 1 the area is π itself ≈ 3.14.
First r = d / 2, then A = πr² (or A = πd² / 4). Diameter 20 means r = 10 and area ≈ 314.16. On this page enter r already — do not put d in the radius field.
Here the primary result is A = πr² (area). Circumference C = 2πr appears beside it for the same r. Starting from diameter or circumference alone lives on the circumference page.
Because the formula uses r². At r = 5 area ≈ 78.54; at r = 10 ≈ 314.16 — about four times larger. Circumference grows only linearly: 2πr.
In theory yes: r = √(A / π). This page goes the other way — from r to A. If you have A and need r, rearrange on paper or use a tool that accepts area as input.
The formula A = πr², Archimedes’ identity A = ½rC, and the historical note below come from recognized references.
Page Updated November 2, 2026.