Example 1 — 3 and 4
- a: 3
- b: 4
- Find c
c = 5
The most famous Pythagorean triple.
Know two sides of a right triangle — we find the third. Solve for the hypotenuse or either leg.
The angle between a and b must be right. Hypotenuse c is always the longest side.
Choose which side to find and enter the two known lengths.
Pythagorean theorem: in a right triangle a² + b² = c², where c is opposite the right angle.
Solve for c: c = √(a² + b²). For a: a = √(c² − b²). Same idea for b.
Everyday use: screen diagonal, shortest path across a field, checking a right angle with a 3-4-5 board.
a² + b² = c²
c = √(a² + b²) ··· a = √(c² − b²) ··· b = √(c² − a²)
c = 5
The most famous Pythagorean triple.
c = 13
Another clean triple.
a = 6
√(100 − 64) = √36 = 6.
b = 8
The 6-8-10 triangle (double 3-4-5).
The longest one — opposite the right angle. If results look wrong, check you did not put a shorter side as c.
Because c² = a² + b² is larger than either square alone. If c is shorter, you get a negative under the square root.
No — any positive lengths work. Triples like 3-4-5 are just easy to check.
So you see which side is which. The scale follows your numbers.
Yes — the sides are a and b, the diagonal is c. Same formula.
Pythagoras does not apply. Use the law of cosines instead.
Measure 3 and 4 on the arms; the diagonal should be 5.
Keep all sides in the same unit. The answer uses that unit too.