City, t_r = 0
v = 13.9 m/s, a = 6, t_r = 0 — like decelerated.
Speed, reaction time, and deceleration (or μ) — thinking distance, braking distance, and total.
Theory and problem: braking. School model without t_r: decelerated motion. Tyre friction: friction force.
Enter values — the result shows up here.
Stopping distance is the sum: during reaction you still roll at constant v (s_react = v·t_r), then brake s_brake = v²/(2a). Together s_total = v·t_r + v²/(2a).
Default t_r = 0.8 s (editable). Check: v = 13.9 m/s, a = 6, t_r = 0 → same as pure decelerated motion; t_r = 1 s → +13.9 m thinking distance.
Road-safety intent. School decelerated motion stays for “s and t without reaction time”.
Instead of a you can enter μ — then a = μg (g = 9.81). Related: momentum, work, friction force.
Chart: s_total vs v at your t_r and a — speed squared stands out.
sreact = v·tr
sbrake = v2/(2a)
stotal = sreact + sbrake
tbrake = v/a; optional a = μ g
v = 13.9 m/s, a = 6, t_r = 0 — like decelerated.
Same v and a, t_r = 1 → +13.9 m.
v = 36 m/s (~80 mph), a = 7, t_r = 0.8.
v = 20 m/s, t_r = 0.8, μ = 0.4.
v = 8 m/s, a = 3, t_r = 0.6.
v = 25 m/s, t_r = 1, μ = 0.7.
v = 8.3 m/s, a = 5, t_r = 0.8.
v = 22 m/s, a = 9, t_r = 0.5.
v = 15 m/s, t_r = 1, μ = 0.1.
Decelerated = school, no t_r. Here = stopping distance with reaction time (road intent).
A typical reaction-time order of magnitude; edit for fatigue, distraction, etc.
Enter a directly or μ — then a = μ·9.81. If both, μ wins.
Yes — enter deceleration magnitude (6, not −6).
Constant-a model. Reality can be worse on wet/ice.
Follow the label (m/s or ft/s). Convert km/h/mph or switch the header.
Braking time v/a only, without t_r. Total time ≈ t_r + t_brake.
In Related — energy and momentum climb with v.
Then s_total = s_brake like decelerated motion.
v1 uses g = 9.81 for a = μg.
Friction force / μ, or school decelerated motion without t_r.