Pressure p = F/S

Force per unit area. The same weight on a smaller patch digs in harder.

Get force from F = m·a. Related: work.

Inputs

Result

Enter values — the result shows up here.

How it works

F S₁ F S₂ p = F / S
Same force F: a small area S₁ (stiletto) means huge pressure, a large S₂ (snowshoe) — tiny.

p = F / S. Same person on a stiletto versus a snowshoe: area changes, weight does not. Smaller S at the same force means higher pressure.

1 Pa = 1 N/m². Atmosphere ≈ 101 kPa. US mode also shows psi. For heels and snowshoes, kPa (or MPa when the area is tiny) stays readable.

Pressure is force spread over area. The same ~700 N person on a stiletto versus a snowshoe leaves a different print because S changes. 1 atm ≈ 101 kPa.

A tyre gauge reads gas pressure inside; this calculator does mechanical contact F/S (for example a simplified tyre patch on asphalt). Both are useful; they answer different questions.

How to use

  1. Enter force.
  2. Enter area > 0.
  3. Read Pa/psi.
  4. Compare areas on the chart.

Formula

p = F ÷ S

Real-life examples

Standing on one foot

All your weight, about 700 N, on one foot of 0.02 m². That is why a single-leg stand digs deeper into wet sand.

Stiletto

The same 700 N on a stiletto heel of 0.0001 m². Pressure spikes so hard that parquet floors have every right to worry.

Snowshoe

Those 700 N again, now spread across a 0.15 m² snowshoe. Pressure drops and the snow suddenly carries you.

Bottle jack

A bottle jack at work: 20000 N on a 0.01 m² piston. Tiny area, huge pressure, and the car rises anyway.

Book on a desk

A thick atlas resting on the desk: a mere 15 N over 0.04 m². Pressure so gentle the desk never even notices.

Vice jaws

Vice jaws clamping 5000 N onto a 0.0005 m² contact. Megapascals appear and the workpiece gives in locally.

Tyre contact patch

A quarter of the car on one tyre: 4000 N on a contact patch of roughly 0.008 m². Your whole grip on the road, palm-sized.

Nail tip

A hammer blow puts 100 N on a nail tip of 0.000002 m². Pressure so extreme the wall simply gives way.

Elephant model

A model elephant: 40000 N of weight over 0.3 m² of four broad feet. Less pressure than a stiletto heel makes.

Suction cup

A suction cup on tile: about 50 N of hold over 0.005 m². Enough to carry a towel, letting go only with that loud pop.

Board on mud

A wheel sinks into mud, so you slide a board under it: 800 N spreads over 0.2 m² and the car stops digging itself in.

Thumb on a thumbtack

Your thumb presses a tack with 20 N; the point measures 0.000001 m². The corkboard accepts it without a fight.

Frequently asked questions

Pa, kPa, bar: how do they relate?

1 Pa = 1 N/m². 1 kPa = 1000 Pa. 1 bar ≈ 100 kPa, near one atmosphere (~101 kPa). For heels and snowshoes, kPa (or MPa when the area is tiny) stays readable.

What about psi in US mode?

1 psi ≈ 6895 Pa. US mode may also show psi so you can compare with bike or car gauges. Remember: gauge psi is air inside the tyre, not always the same as contact-patch F/S on the road.

Why does a heel sink while a snowshoe does not?

Heel area is tiny, so p = F/S spikes at the same weight. A snowshoe spreads those ~700 N over a large S: pressure drops and snow holds. It is the cleanest everyday picture of the formula.

Is tyre pressure the same as this formula?

Related, not identical. A gauge reads the gas pressure inside. Contact F/S is a simplified "force on the patch" story. Both are useful; they answer different questions.

What if area is zero?

Division by zero. A mathematical point contact is an idealisation; real tips still have some area. Enter S > 0, even 0.000002 m² for a nail point.

How do I get force from body mass?

When standing, F ≈ m·g (g ≈ 9.81 m/s²). A 70 kg person is about 700 N. Divide by one foot, two feet, or snowshoe area: that is why one-leg stands feel harsher on soft ground.

What about fluid pressure ρgh?

Different chapter: fluid pressure grows with depth. Here you have mechanical F/S: vice jaws, nails, jacks, snow. Do not mix ρgh with shoe area unless you are doing a lake problem.

When do results jump to MPa?

When F is large and S is tiny: vices, nails, hydraulics. 5000 N on 0.0005 m² is 10 MPa. Metal yields locally, wood splits. Prefixes just shorten the writing.

How do I estimate shoe contact area?

Roughly: sole length × width in metres, or the outline on paper. For stiletto-versus-snowshoe comparisons, an order of magnitude is enough; you do not need square-millimetre precision.

Why chart different areas?

To show that at fixed F, pressure falls as S grows. Same weight, different footwear: stiletto to snowshoe. One glance explains snow, mud, and soft floors.