Example 1
An adult standing on one leg: the whole weight, about {{u:700:force:0}}, rests on a foot of {{u:0.02:area-m2:2}}. That is why a single footprint in wet sand is deeper than two.
p = {{u:35:press-kpa}}
Enter force F and contact area A. The calculator computes pressure with p = F/A. At 700 N and 0.02 m² the result is 35 kPa; at the same 700 N and 0.0001 m² it is 7 MPa. The panel also shows bar and psi. This is not hydrostatic pressure ρgh and not a “solve for force from pressure” mode — inputs are F and A.
Enter force and contact area. Pressure, conversions, and the scale appear here.
The pressure of a fluid column has its own calculator: hydrostatic pressure p = ρ g h. The article on pressure from force and area covers the same relation in more depth.
Pressure measures how concentrated a force is on a surface. The definition is a quotient: p = F/A, where F is the force perpendicular to the surface and A is the area over which that force spreads. Many European textbooks write the area as S, hence p = F/S in this page address; the physics is identical. The SI unit of pressure is the pascal: 1 Pa = 1 N/m². This is the textbook definition (Halliday, Resnick, Walker, Fundamentals of Physics; Young, Freedman, University Physics), and the unit honors Blaise Pascal.
The calculator uses the two numbers you enter: force F and area A. The result is their quotient. For 700 N and 0.02 m² you get 700 / 0.02 = 35,000 Pa, or 35 kPa. For the same 700 N on a 0.0001 m² heel the result is 7,000,000 Pa, or 7 MPa — two hundred times more, because the area is two hundred times smaller.
What the result panel shows. Besides the pressure in a fitting unit (Pa, kPa, or MPa — or psi in US mode) the calculator reports the same value in pascals, bar, and psi, the multiple of standard atmospheric pressure (1 atm = 101,325 Pa), and the height of a water column that would exert the same pressure: h = p/(ρ·g) with ρ = 1,000 kg/m³ and g = 9.80665 m/s². For 35 kPa that is about 3.57 m (11.7 ft) of water. The logarithmic scale under the result places your value between 1 Pa and 1 GPa next to reference points: atmospheric pressure, a typical car tire, and the bottom of the Mariana Trench.
What this calculator does not compute. It does not compute the pressure of a fluid column from density and depth (a separate page handles p = ρ g h), it does not resolve an inclined force into components, and it does not model the uneven contact-pressure distribution under a real heel or tire. The result is the average pressure over the whole area A, assuming the force acts perpendicular to the surface.
The unit switch in the header toggles the fields between lbf and ft² (US) and N and m² (metric) and the main result between psi and pascals; SI values in the text stay as the reference. A comma and a period in the fields mean the same decimal separator. The area must be greater than zero, because division by zero has no physical meaning: no contact surface, no pressure.
Examples on this page: 700 N on 0.02 m² → 35 kPa; 700 N on 0.0001 m² → 7 MPa; 700 N on 0.15 m² → about 4.67 kPa; 20,000 N on 0.01 m² → 2 MPa; 100 N on 0.000002 m² → 50 MPa. The “Fill this example” button enters the same numbers into the fields and refreshes the result panel, the scale, and the chart.
p = F / A
[p] = N/m² = Pa; 1 kPa = 1,000 Pa, 1 MPa = 1,000,000 Pa, 1 bar = 100,000 Pa, 1 atm = 101,325 Pa, 1 psi ≈ 6,894.76 Pa
Model: pressure as the quotient of normal force and area (SI definition, BIPM). The rearrangements F = p·A and A = F/p follow from the same formula, but this calculator solves for p only. Order of computation: p = F / A in SI units, then conversions to bar, psi, atm, and the water column h = p/(ρ·g).
Pressure p is defined as the ratio of the force F acting perpendicular to a surface to the area A of that surface: p = F/A. It is a scalar — unlike force it has no direction, although the force that produces it does. If the force is not distributed evenly, the quotient gives the average pressure; the pressure at a point is defined by the limit p = dF/dA as the area shrinks to zero.
The SI unit of pressure is the pascal, 1 Pa = 1 N/m² = 1 kg·m⁻¹·s⁻². The name was adopted by the 14th General Conference on Weights and Measures in 1971 in honor of Blaise Pascal. The pascal is small on an everyday scale: standard atmospheric pressure at sea level is about 101,325 Pa, which is why practice uses hectopascals (meteorology), kilopascals (engineering), and megapascals (strength of materials). In the United States the pound-force per square inch (psi) remains common; 1 psi = 6,894.757 Pa.
The quantitative notion of pressure grew out of studies of the atmosphere. In 1643 Evangelista Torricelli built the mercury barometer and showed that air exerts a pressure balanced by a mercury column about 76 cm high. In 1648 Blaise Pascal organized a measurement on the Puy de Dôme (carried out by his brother-in-law Florin Périer): the mercury column shortened with altitude, confirming that pressure comes from the weight of the air.
Pascal’s posthumously published Traité de l’équilibre des liqueurs (1663) states the principle now called Pascal’s law: pressure applied to a confined fluid is transmitted equally in all directions. That principle is behind the hydraulic press and the bottle jack that appear among the examples on this page. Pascal’s name entered the SI only three centuries later.
The formula p = F/A correctly describes a force acting perpendicular to a surface and spread evenly over it. When the force acts at an angle θ to the normal, only its normal component F·cos θ produces pressure, while the tangential component F·sin θ produces shear stress, not pressure. This calculator assumes θ = 0, so the value in the Force field should already be the perpendicular component.
The second assumption concerns uniformity. A foot on sand, a tire on asphalt, or a vise jaw on wood does not press every square millimeter of the contact equally. The calculator’s result is then the average pressure: local values can be noticeably higher where the load concentrates. For school problems and engineering estimates the average pressure is usually the right quantity; for a failure analysis of the material the full contact-pressure distribution is needed.
Step 1. A force F acts perpendicular to a flat surface of area A. By definition p = F/A; in units, [N]/[m²] = [Pa]. Step 2. If the force is the weight of a body of mass m, then F = m·g, so p = m·g/A. Seventy kilograms at g = 9.81 m/s² give about 687 N — hence 700 N as a rounded example of an adult’s weight.
Step 3. The hydrostatic formula is a special case of the same definition. Consider a column of liquid with density ρ, height h, and base area A. Its mass is m = ρ·A·h, its weight F = ρ·A·h·g, and the pressure on the base F/A = ρ·g·h. The area cancels, which is why pressure at depth h does not depend on the shape of the container — the so-called hydrostatic paradox. Step 4. Inverting this relation, the calculator reports the height of a water column h = p/(ρ·g) that would exert the computed pressure; for 35 kPa and water at 1,000 kg/m³ that is about 3.57 m, or 11.7 ft.
In continuum mechanics the internal forces are described by the Cauchy stress tensor σ (Augustin-Louis Cauchy, 1822). Mechanical pressure is its isotropic part: p = −(1/3)·tr σ = −(σ₁₁ + σ₂₂ + σ₃₃)/3, with the convention that tension is positive and compression negative. In a fluid at rest the shear stresses vanish and the tensor reduces to −p·I, so the pressure is the same in every direction — Pascal’s law in tensor language.
The contact of two solids over a small patch is not uniform. Heinrich Hertz, in Über die Berührung fester elastischer Körper (1882), derived that for a sphere pressed against a plane the contact radius grows as F^(1/3) and the maximum pressure at the center of the patch is 1.5 times the mean pressure F/(π·a²). This theory is applied to bearings, wheels, and gear teeth. For this page it means one thing: p = F/A gives the average, and the true maximum under a nail or a thumbtack is higher still.
Conversion factors used by the calculator: 1 bar = 100,000 Pa (exactly), 1 atm = 101,325 Pa (exactly, by definition of the standard atmosphere), 1 psi = 6,894.757 Pa (pound-force per square inch), 1 mmHg = 133.322 Pa, 1 Torr = 101,325/760 Pa ≈ 133.322 Pa, 1 hPa = 100 Pa. These values appear in the BIPM SI Brochure and NIST Special Publication 811; NIST recommends the pascal and lists other units only as conversions.
Engineering distinguishes absolute pressure (measured from vacuum) from gauge pressure (measured from atmospheric pressure). The gauge on a compressor or a tire reads gauge pressure: “32 psi in a tire” means roughly 47 psi (about 320 kPa) absolute. The quotient p = F/A in this calculator is simply the pressure a force exerts on a surface; it does not add atmospheric pressure, which acts on both sides of most objects and cancels in the balance.
Orders of magnitude for orientation on the logarithmic scale: 1 Pa is roughly the pressure of a dollar bill lying flat on a table; 10–100 kPa is the pressure under a human foot; 101.325 kPa is one atmosphere; 200–250 kPa (29–36 psi) is a passenger-car tire gauge pressure; about 110 MPa (16,000 psi) acts at the bottom of the Mariana Trench (depth about 11 km); 1 GPa is the order of pressure in diamond-synthesis presses.
The definition, unit, and derivation come from general-physics textbooks and metrology documents: D. Halliday, R. Resnick, J. Walker, Fundamentals of Physics (chapter on fluids), Wiley; H. D. Young, R. A. Freedman, University Physics, chapter “Fluid Mechanics”; R. P. Feynman, R. B. Leighton, M. Sands, The Feynman Lectures on Physics, Vol. II, chapters 31 (tensors) and 38–39 (elasticity); L. D. Landau, E. M. Lifshitz, Theory of Elasticity; K. L. Johnson, Contact Mechanics, Cambridge University Press, 1985; H. Hertz, Über die Berührung fester elastischer Körper, Journal für die reine und angewandte Mathematik, vol. 92, 1882; B. Pascal, Traité de l’équilibre des liqueurs, 1663; BIPM, The International System of Units (SI), 9th edition; NIST SP 330 and SP 811. This page is for educational purposes.
p is pressure, F the normal force, A the contact area. For 700 N and 0.02 m² the result is 35 kPa.
An adult standing on one leg: the whole weight, about {{u:700:force:0}}, rests on a foot of {{u:0.02:area-m2:2}}. That is why a single footprint in wet sand is deeper than two.
p = {{u:35:press-kpa}}
The same {{u:700:force:0}} on a stiletto heel of {{u:0.0001:area-m2:4}}. Pressure rises two hundred times and parquet floors keep permanent dents.
p = {{u:7:press-mpa}}
Those {{u:700:force:0}} again, now spread across a {{u:0.15:area-m2:2}} snowshoe. Pressure drops below the bearing capacity of snow and the walker stops sinking.
p ≈ {{u:4.6667:press-kpa}}
A bottle jack at work: {{u:20000:force:0}} on a {{u:0.01:area-m2:2}} piston. A small area and a large force produce a pressure that the oil transmits to the second piston and lifts the car.
p = {{u:2:press-mpa}}
A thick atlas resting on a desk: a mere {{u:15:force:0}} over {{u:0.04:area-m2:2}}. The pressure is so small that it leaves no mark on the wood.
p = {{u:375:press-pa}}
Vise jaws clamping {{u:5000:force:0}} onto a {{u:0.0005:area-m2:4}} contact. Megapascals appear locally and soft wood deforms.
p = {{u:10:press-mpa}}
One tire carries a quarter of the car’s weight: {{u:4000:force:0}} on a contact patch of roughly {{u:0.008:area-m2:3}}. The whole contact between tire and road is about the size of a palm.
p = {{u:500:press-kpa}}
A hammer blow puts {{u:100:force:0}} on a nail tip of {{u:0.000002:area-m2:6}}. The pressure is so high that the wood fibers part.
p = {{u:50:press-mpa}}
An elephant in a simplified model: {{u:40000:force:0}} of weight spread over four broad feet with a total area of {{u:0.3:area-m2:1}}. The pressure is lower than under a stiletto heel.
p ≈ {{u:133.333:press-kpa}}
A suction cup on tile: about {{u:50:force:0}} of hold over {{u:0.005:area-m2:3}}. That is enough to hold a towel; the cup lets go only when air is admitted.
p = {{u:10:press-kpa}}
A wheel sinks into mud, so a board goes under the tire: {{u:800:force:0}} spreads over {{u:0.2:area-m2:1}} and the car stops digging in.
p = {{u:4:press-kpa}}
A thumb presses a tack with {{u:20:force:0}}; the point measures {{u:0.000001:area-m2:6}}. The corkboard accepts it with almost no resistance.
p = {{u:20:press-mpa}}
Pressure is the quotient of the force perpendicular to a surface and the area of that surface: p = F/A. The calculator divides the entered force by the entered area and reports the result in pascals (or psi in US mode), together with kilopascals or megapascals, bar, psi, and the multiple of atmospheric pressure.
In US mode, the default for this page, force is in pounds-force [lbf] and area in square feet [ft²], and the main result is in psi. After switching the header to metric, the fields take newtons [N] and square meters [m²], and the result is in pascals. One square centimeter is 0.0001 m², not 0.01.
A thousand pascals is 1 kPa and a million is 1 MPa. One bar is exactly 100,000 Pa, one standard atmosphere is 101,325 Pa, and one psi is 6,894.757 Pa. The result panel performs these conversions automatically; for example, 35 kPa is 0.35 bar and about 5.08 psi.
Because the area sits in the denominator of p = F/A. If the area shrinks two hundred times, the pressure grows two hundred times: 700 N on a 0.02 m² foot is 35 kPa, while the same 700 N on a 0.0001 m² heel is 7 MPa. That is why blades are thin and snowshoes are wide.
Here the pressure comes from any force acting on a surface: p = F/A. Hydrostatic pressure p = ρ g h is a special case in which the force is the weight of a liquid column of density ρ and height h. The panel shows the inverse of that relation: the height of a water column that would exert the computed pressure.
Not quite. Stress is described by the Cauchy tensor, which has normal and shear components. Pressure is only its isotropic part — the average of the normal components with a minus sign. In a fluid at rest the shear stresses vanish and pressure describes the whole state; in a solid under a heel the contact distribution is uneven, and p = F/A gives its average value.
Only the component perpendicular to the surface, F·cos θ, produces pressure, where θ is the angle between the force and the normal. The calculator assumes the entered force is already that component. The tangential component F·sin θ produces shear stress and friction, which this calculator does not compute.
The result is the pressure the entered force exerts on the entered area, without adding atmospheric pressure. For a foot, a vise, or a piston that is the right quantity, because the atmosphere acts on both sides and cancels. Tire gauges read gauge pressure relative to the atmosphere, not absolute pressure.
No. The switch only changes the input and display units: lbf versus N, ft² versus m², psi versus Pa. The values entered in the fields are converted to SI units, divided according to p = F/A, and presented in the selected system. The physics stays the same.
Division by zero is undefined, and physically a force concentrated on zero area would mean infinite pressure. Real materials deform and form a finite contact patch, which Hertz contact theory describes. The calculator requires an area greater than zero and shows a message until that condition is met.
Not directly. If the force is a weight, multiply the mass by the acceleration of gravity: F = m·g, where g ≈ 9.81 m/s² (32.2 ft/s²). A mass of 70 kg gives about 687 N, which you can enter in the force field. The separate F = m·a calculator computes that product for any acceleration.
The scale runs from 1 Pa to 1 GPa, and each tick marks a tenfold increase. The marker shows the computed pressure, and the gray dots are references: atmospheric pressure 101.3 kPa, a typical car-tire gauge pressure of about 220 kPa (32 psi), and the pressure at the bottom of the Mariana Trench, about 110 MPa. The scale is for orientation; it does not replace the conversions in the panel.
Divide force F (in newtons) by area A (in m²). The result is in pascals: 1 Pa = 1 N/m². For 700 N and 0.02 m² you get 35,000 Pa, or 35 kPa.
10,000 Pa, or 10 kPa. 500 / 0.05 = 10,000. That is a classic textbook example; the calculator uses the same SI units.
1 cm² = 0.0001 m² (10⁻⁴), not 0.01. One hundred cm² is 0.01 m². A two-order error in area ruins the pressure by the same factor.
Not as the primary result. Inputs are force and area; the result is pressure. From pressure and area you recover force with F = p·A outside this page or in another tool’s mode.
35 kPa. That is the first example on this page. The same 700 N on a 0.0001 m² heel is 7 MPa — two hundred times larger because the area is two hundred times smaller.
The definition, unit, history, and derivation below come from recognized physics and metrology sources.
Page updated November 3, 2026.