Resistors in Parallel Calculator

Type R1 [Ω] and R2 [Ω]. The calculator computes Rz = R1·R2/(R1+R2): two 100 Ω resistors are 50 Ω, and 60 Ω and 40 Ω are 24 Ω. In parallel the voltage is the same and currents add.

Series: Rz = R1+R2. Ohm's law: U = I·R.

Inputs

Result

Resistance R1 (Ω) and Resistance R2 (Ω). The result shows up here.

How it works

R₁ R₂ Rᵢ = R₁R₂ / (R₁+R₂)
Parallel resistors: same voltage, currents add.

Parallel equivalent resistance obeys 1/Rz = 1/R1 + 1/R2, or Rz = R1 R2 / (R1+R2). At 100 Ω and 100 Ω you get 50 Ω. At 60 Ω and 40 Ω: 2400 / 100 = 24 Ω. At 10 Ω and 10 Ω you get 5 Ω. Rz is always smaller than the smaller of the pair, because current has two paths.

The form has two fields: R1 and R2 in ohms, both positive. The result is in ohms. Type 2.2 kΩ as 2200. A comma and a period mean the same R: 47,5 and 47.5.

R = 0 will not run: the reciprocal of zero does not exist. Both fields need a positive number before 50 Ω appears. In parallel the voltage on both is the same, and currents add: I1 + I2 = Iz.

Series Rz = R1 + R2 grows. Here Rz drops. Ohm's law U = I R already takes one R, for example this Rz. This calculator combines two paths; it does not compute watts.

Two identical R values give half: 100 || 100 = 50. A very large R2 barely changes Rz, because 1/R2 is small. Three branches take two steps: first a pair, then that Rz with the third.

Type 100 and 100, click Calculate, and check 50 Ω. Then 60 and 40: 24 Ω. The calculator computes product over sum; it does not lay out a bridge.

How to use

  1. In the first field enter R1 in ohms, for example 100. Both R values must be positive.
  2. In the second field enter R2 in ohms, for example 100 or 40.
  3. Click Calculate. Two 100s give 50 Ω, because 1/Rz = 1/100 + 1/100. 60 and 40 give 24 Ω.
  4. Zero in R1 or R2 is rejected. Both fields need a positive number.
  5. For the sum R1+R2, open resistors in series. One R for U = I R is on Ohm's law.

Formula

Rz = R1·R2 / (R1 + R2)

R1 > 0, R2 > 0.

Letters of two parallel resistors

In parallel Rz = R1·R2/(R1+R2). Two 100 Ω resistors give 50 Ω. 60 Ω and 40 Ω give 24 Ω. Shared voltage, currents add.

Rz
Parallel equivalent [Ω]. Always smaller than the smaller of R1 and R2. Two equals give half.
R1
First branch [Ω], for example 60. Current in it is U/R1.
R2
Second branch [Ω], for example 40 Ω. R1·R2/(R1+R2) gives 24 Ω.

Real-life examples

Example 1

Rz = 50 Ω.

Example 2

Rz = 24 Ω.

Example 3

Rz = 5 Ω.

Example 4

Rz = 132 Ω.

Example 5

Rz = 500 Ω.

Example 6

Rz ≈ 32 Ω.

Example 7

Rz = 3 Ω.

Example 8

Rz ≈ 91 Ω.

Example 9

Rz = 1 Ω.

Example 10

Rz = 100 Ω.

Ways to use this calculator

  • You check two 100 Ω resistors: 50 Ω.
  • You compute 24 Ω from 60 Ω and 40 Ω.

Frequently asked questions

How much Rz with two 100 Ω?

Equivalent resistance is 50 Ω. 1/Rz = 1/100 + 1/100, or 100×100 / 200. Two equal resistors in parallel give half.

How much at 60 Ω and 40 Ω?

You get 24 Ω. The product 60×40 over the sum 100. Rz is smaller than 40 Ω, the smaller branch.

Which units do I type?

Both resistances R1 [Ω] and R2 [Ω], both positive. Result Rz [Ω].

How is this different from series?

In parallel 1/Rz = 1/R1 + 1/R2 and Rz is smaller than each. Series adds: Rz = R1 + R2.

Does a comma in 47.5 work?

Yes. 47.5 and 47,5 are the same R [Ω]. A comma and a period mean the same value.

Is the voltage the same?

Yes. In parallel both branches sit on the same U [V]. Currents I = U/R add, which is why Rz is smaller.

Why is Rz smaller?

Because current has two paths. More current at the same U means a smaller equivalent resistance.

Where is series?

On the series-resistors page. There a sum. Here the product over the sum.

What about R = 0?

Zero ohms is a short. The calculator cannot form a clean Rz then, because you divide by R1+R2 with a zero branch.

How much at 10 Ω and 10 Ω?

You get 5 Ω. Two equal resistors in parallel always give half of one.

Knowledge sources

The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.

Page updated in 2026.