Example 1
I = 0.5 A, R = 100 Ω → U = 50 V.
Enter any two of voltage, current and resistance. The calculator fills the third from U = I·R. 0.5 A through 100 Ω is 50 V. 12 V across 6 Ω is 2 A. 24 V at 3 A is 8 Ω.
Need resistance from voltage and current: R = U/I. Power next door: P = U·I.
Any two of I, R or U. The result shows up here.
Ohm's law ties current, resistance, and voltage in one product: U = I·R. At 0.5 A and 100 Ω you get 50 V. At 1 A and 12 Ω you get 12 V, a typical car rail. At 2 A and 47 Ω you get 94 V. At 10 A and 23 Ω you get 230 V, household order of magnitude, still just two field numbers, not a model of the whole installation.
The first field is current I in amperes, the second is resistance R in ohms. The result is in volts. If you have 2.2 kΩ, type 2200, not 2.2: the field does not know the kilo prefix. 20 mA is 0.02 A; at 1000 Ω that is 20 V, as on the page. A comma and a period are the same current, so 0,5 and 0.5 both run.
This calculator computes U from I and R and does not invert the formula. You know voltage and current and want ohms? Open the R = U/I page. Series and parallel live next door too: here you already type one R, you do not build a network from several resistors.
Zero amperes is rejected, because U = 0·R says nothing about the circuit, and the sibling R = U/I does not exist at zero current. Zero ohms will not run either: a homework line would give U = 0, a real wire always keeps some resistance. A negative I is current direction, not a unit mix-up.
Once you have U, power is next door as P = U·I. At 50 V and 0.5 A that is 25 W. There is one Ohm triplet, only the unknown changes. I = U/R at a fixed 230 V is a different page: there current falls as R rises. Here you type I and R and get U.
Type 0.5 and 100, click Calculate, and match 50 V. Then 3 A and 4 Ω: 12 V again, a different pair on the same rail. The unit switch does not rewrite ohms into another resistance scale; you stay with amperes, ohms, and volts.
U = I · R
SI units: V, A, Ω. I and R from the fields, U on the page.
This calculator multiplies current by resistance. 0.5 A × 100 Ω = 50 V, the first example pair, not a model of the whole installation.
I = 0.5 A, R = 100 Ω → U = 50 V.
U = 12 V, R = 6 Ω → I = 2 A.
U = 24 V, I = 3 A → R = 8 Ω.
I = 0.02 A, R = 1000 Ω → U = 20 V.
I = 3 A, R = 4 Ω → U = 12 V.
I = 0.1 A, R = 220 Ω → U = 22 V.
I = 5 A, R = 0.5 Ω → U = 2.5 V.
Small current, series resistor.
Large current, low resistance.
1 mA through 10 kΩ → 10 V.
U = 0.5 × 100 = 50 V. 1 A and 12 Ω is 12 V. 10 A and 23 Ω is 230 V. Always I times R.
Amperes and ohms. The result is in volts. 2.2 kΩ is 2200 Ω in the field, not 2.2. 20 mA is 0.02 A.
The calculator rejects zero amperes. U = 0·R says nothing about the circuit, and R = U/I does not exist at zero.
On paper U would be 0. A real circuit always has some resistance, so zero ohms is rejected here.
On the resistance-from-Ohm page. Here you compute U, there R. Same triplet, different unknown.
P = U·I on the power page. 50 V and 0.5 A is 25 W. This calculator stops at volts.
Series: a sum. Parallel: product over sum. Sibling pages. The calculator uses one R already.
That is I = U/R, not this card. Here you type I and R and get U. The unknown sits on the other side of the formula.
Yes. 0,5 and 0.5 are the same current. The calculator does not require a period.
It is the 230 V order of magnitude, not a model of the installation. The calculator multiplies two numbers and does not check a breaker.
Ohm’s law in this calculator is U = I × R or R = U/I. Units follow SI; NIST SP 330 and BIPM define the volt, ampere and ohm.
Page updated in 2026.