Example 1
Yellow, f = 5e14 Hz -> E ≈ 2.07 eV.
Enter frequency. The calculator multiplies it by Planck’s constant and you get the energy of one photon in joules and in eV. Yellow 5e14 Hz is about 2.07 eV. When you know nanometers instead of hertz, open E = hc/λ.
From wavelength: E = hc/λ. Inverse: λ = hc/E. Wavelength: λ = v/f.
Frequency f (Hz). The result shows up here.
Light and radio are waves, but the energy arrives in packets. One packet, a photon, has E = h·f. h = 6.62607015e-34 J·s is fixed; you do not type it. Higher frequency means more energy per photon, not brighter light and not louder radio. Brightness is how many photons per second, a different sum.
Take yellow light from a problem, f = 5e14 Hz. E = h·f = 3.313e-19 J. A joule is too large for one photon, so you divide by 1.602176634e-19 J/eV and get 2.07 eV. Ultraviolet at 1e15 Hz is already 4.14 eV, twice as much, because f is twice as high. X-rays at 3e17 Hz reach 1240 eV, or 1.24 keV.
Radio and microwaves sit many orders lower. Wi-Fi at 2.4 GHz is about 9.9e-6 eV. A 2.45 GHz oven is about 1.0e-5 eV. FM at 100 MHz is about 4.1e-7 eV. Same formula, different shelf. A 440 Hz fork would formally give 1.8e-12 eV, but sound is not a photon: it is a wave in air, with no h in that sense.
f has to be positive. c does not enter E = h·f. The speed of light appears only when you start from wavelength: E = hc/λ, because in vacuum f = c/λ. Hertz does not follow the US header. Energy stays in J and eV. The chart of E versus f is a straight line through the origin.
The form needs one field. Type 5e14 and read 2.07 eV. 1e15 gives 4.14 eV. 2.45e9 gives order 1e-5 eV. A comma and a period both parse. If the problem gives T, get f = 1/T first, then come back here.
When you know λ in nanometers, open E = hc/λ and type meters (600 nm is 6e-7). When you know eV and want λ back, open λ = hc/E. Here you stay with frequency.
E = h · f
h = 6.62607015×10⁻³⁴ J·s (fixed). 1 eV = 1.602176634×10⁻¹⁹ J. f > 0.
One photon carries E = h·f. Yellow 5×10¹⁴ Hz times h is 3.313×10⁻¹⁹ J, about 2.07 eV.
Yellow, f = 5e14 Hz -> E ≈ 2.07 eV.
f = 5.6e14 Hz -> E ≈ 2.32 eV.
f = 1e15 Hz -> E ≈ 4.14 eV.
f = 2.45e9 Hz -> E ≈ 1.0e-5 eV.
f = 2.4e9 Hz -> E ≈ 9.9e-6 eV.
f = 1e8 Hz -> E ≈ 4.1e-7 eV.
f = 3e17 Hz -> E ≈ 1240 eV.
f = 440 Hz -> E ≈ 1.8e-12 eV (sound, not a photon).
E = h·f ≈ 3.313e-19 J, or 2.07 eV. That is yellow light from many problems.
h = 6.62607015e-34 J·s. It is fixed in the calculator. Same h as in E = hc/λ.
A joule is too large for one visible photon. 1 eV = 1.602176634e-19 J, so yellow comes out near 2 eV.
E ≈ 4.14 eV. Twice the f of 5e14, twice the energy per photon.
No. Sound is a mechanical wave in air. E = h·f is for EM radiation: radio, light, X-rays.
In vacuum λ = c/f, then E = hc/λ. Or open E = hc/λ directly when you know λ instead of f.
About 9.9e-6 eV. A 2.45 GHz oven is about 1.0e-5 eV. Many orders below light.
No. c appears when you start from λ: E = hc/λ. Here you know f, so h is enough.
Here you compute the energy of one photon. Beam power is N·E / time; that field is not here, because it is a different sum.
E ≈ 1240 eV, or 1.24 keV. That is already soft X-ray, not a light bulb.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.