Example 1
λ = 0.78 m, f = 440 Hz -> v ≈ 343 m/s.
Enter wavelength and frequency. The calculator multiplies λ by f and you get the speed in the medium. 0.78 m at 440 Hz is about 343 m/s, classroom air. When you know v and f and want λ, open λ = v/f.
Inverse: λ = v/f. Photon energy: E = h·f. Doppler: f′.
Wavelength λ (m) and Frequency f (Hz). The result shows up here.
In one period T = 1/f the wave advances by one wavelength λ. So v = λ/T, and after you substitute T = 1/f you get v = λ·f. That is the same relation as λ = v/f: you only change which quantity is unknown. Here you know the crest spacing and how often crests pass, and you want how fast the medium carries the wave.
Measure λ with microphones at a 440 Hz fork and you get about 0.78 m. The product 0.78 × 440 = 343.2 m/s, about 343 m/s on the page. You have hit sound in air at 20 °C. The pair 0.34 m and 1000 Hz gives 340 m/s, the same order. A 6.86 m bass at 50 Hz returns to 343 m/s again: the same room, a different note.
For radio and light the numbers jump by orders of magnitude. A 3 m dipole and 100 MHz give v = 3e8 m/s. Wi-Fi at 12.5 cm (0.125 m) and 2.4 GHz gives the same c. Type 600 nm light as 6e-7 m; at f = 5e14 Hz the product is 3e8 m/s. If v comes out clearly different from c, the wave is not in vacuum or you typed nanometers as meters.
λ and f have to be positive. The chart of v versus f at fixed λ is a straight line: higher f, larger v, because more cycles per second fit in the same crest spacing. T = 1/f sits beside it, because v = λ/T is the same thought. At 440 Hz, T ≈ 0.00227 s and 0.78 / 0.00227 ≈ 343 m/s.
λ follows the header in m or ft. f stays in hertz. The v result shows m/s and, in US mode, ft/s. On the form, type λ in meters: 600 nm is 6e-7, not 600. The calculator example 0.78 and 440 gives air. 1.48 m and 1000 Hz give 1480 m/s, sound in water.
When you know v and f and want λ (antenna, speaker, color), go back to λ = v/f. A photon from that f is E = h·f. Loudness does not change v: a shout and a whisper travel at the same speed in air.
v = λ · f
λ > 0, f > 0.
Here the unknown is v = λ·f. A measured spacing of 0.78 m at 440 Hz builds 343.2 m/s, classroom air.
λ = 0.78 m, f = 440 Hz -> v ≈ 343 m/s.
λ = 0.34 m, f = 1000 Hz -> v ≈ 340 m/s.
λ = 3 m, f = 1e8 Hz -> v = 3e8 m/s.
λ = 0.125 m, f = 2.4e9 Hz -> v = 3e8 m/s.
λ = 6e-7 m, f = 5e14 Hz -> v ≈ c.
λ = 6.86 m, f = 50 Hz -> v ≈ 343 m/s.
λ = 1.48 m, f = 1000 Hz -> v = 1480 m/s.
λ = 3.41 m, f = 8.8e7 Hz -> v ≈ 3e8 m/s.
v = 0.78 × 440 = 343.2 m/s, about 343 m/s on the page. That is sound in air near 20 °C.
As 6e-7 meters. The field holds SI. Typing 600 would be 600 m × f, not light.
c is light in vacuum. Sound is 343 m/s; a water wave is a few m/s. 440 Hz and 0.78 m are air, not a photon.
T ≈ 0.00227 s. v = λ/T is the same as v = λ·f: 0.78 / 0.00227 ≈ 343 m/s.
When you know v and f and want λ (antenna, speaker, color). Here you know λ and f and want v.
0.125 × 2.4e9 = 3e8 m/s. That is Wi-Fi in air, order c.
For light in vacuum that is usually a λ unit mistake. For sound, v is much smaller than c and should be.
Not in this model. v depends on the medium and the wave type, not on amplitude. A shout and a whisper share the same speed.
v = 1480 m/s. That is sound in water, not in a classroom.
No. Frequency is positive. In the Doppler formula the sign belongs to the source speed, not to the wave f itself.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.