Example 1
U = 12 V, I = 2 A, t = 60 s → W = 1440 J.
Type U [V], I [A] and t [s]. The calculator computes W = U·I·t: 12 V, 2 A and 60 s is 1440 J, and 230 V and 1 A for 3600 s is 828,000 J. Negative time is refused.
Circuit power: P = U·I. Heat in a resistor: Q = I²·R·t.
Voltage U (V), Current I (A) and Time t (s). The result shows up here.
Electrical work is the energy voltage and current deliver over time t: W = U·I·t. At 12 V, 2 A and 60 s you get 1440 J. A heater at 230 V and 1 A for one hour, 3600 s, is 828,000 J. At constant power that is the same as P·t, because P = U·I: 24 W for 60 s is again 1440 J.
The form has three fields in this order: voltage U in volts, current I in amperes, time t in seconds. The result is in joules. Type a minute as 60 and an hour as 3600, not as 1. A comma and a period mean the same current: 0,5 and 0.5.
Negative time will not run. Typed zero in U, I, or t gives W = 0: no voltage, no current, or no seconds. All three fields need a number before 1440 J appears. 1 kWh is 3,600,000 J (1000 W for 3600 s); this calculator stays in joules and does not convert to kWh.
Power P = U·I is on the neighbouring page, without time. Here energy in joules, there watts. Mechanical W = F·s uses the same joule unit and a different formula: force and distance there, a circuit here.
Joule heat Q = I² R t is another calculator. On a purely thermal resistor W and Q can be the same number. Here you compute work delivered to the circuit, not necessarily heat in the resistor.
USB at 5 V and 0.5 A for 120 s is 300 J. An LED at 3 V and 0.02 A for one hour is 216 J. Same joules, different scales: the calculator does not guess the device, it multiplies three field numbers.
W = U · I · t
Alternatively at steady power: W = P · t with P = U · I. Unit: J.
Electrical work here is W = U·I·t. 12 V, 2 A and 60 s is 1440 J. 230 V and 1 A for an hour is 828,000 J.
U = 12 V, I = 2 A, t = 60 s → W = 1440 J.
One hour heater run: W = 828000 J.
USB: W = 300 J.
Short motor start: W = 2400 J.
LED for one hour: W = 216 J.
10 min: W = 36000 J.
EV battery: W = 72000 J.
9 V battery, half an hour: W = 1620 J.
One minute: W = 27600 J.
12 min: W = 43200 J.
Work is 1440 J. That is 12 × 2 × 60. At power P = 24 W it is the same 24 × 60, only here the fields are U, I and t.
Work is 828,000 J. One hour at 230 V and 1 A, a 230 W heater for 3600 s.
Voltage U [V], current I [A], time t [s]. Result W [J]. Type an hour as 3600, not as 1.
Here energy W = U I t in joules. There power P = U I in watts, with no time field. Same U and I pair, different unknown.
Same unit W [J]. Different formula: a circuit with U, I and t here. Force and path there, with no amperes.
Yes. 0.5 and 0,5 are the same I [A]. A comma and a period mean the same value.
On the Q = I² R t page. Here work delivered to the circuit, not necessarily heat on a resistor.
Yes. 1000 W for 3600 s. This calculator reports joules, not kilowatt-hours. 828,000 J is not yet 1 kWh.
The calculator refuses negative time. Zero seconds gives W = 0 J. U and I still need a number.
Work is 300 J. That is 5 × 0.5 × 120. A small supply, two minutes.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.