Example 1
B = 0.5 T, I = 2 A, l = 0.1 m -> F = 0.10 N.
Type B [T], I [A] and l [m]. The calculator computes F = B I l at 90°: 0.5 T, 2 A and 0.1 m is 0.1 N, and 1.5 T, 8 A and 0.2 m is 2.4 N. Zero amperes gives zero newtons.
Current: I = Q/t. Faraday induction: EMF = ΔΦ/Δt.
Induction B (T), Current I (A) and Length l in the field (m). The result shows up here.
Force on a straight wire in a B field at 90° is F = B I l. At 0.5 T, 2 A and 0.1 m you get 0.1 N. At 1.5 T, 8 A and 0.2 m you get 2.4 N. At 0.8 T, 0.5 A and 0.02 m you get 0.008 N. At 0.2 T, 10 A and 0.25 m you get 0.5 N.
The form has three fields: B in teslas, I in amperes, l in meters. The result is in newtons. The angle is always 90°, the maximum. Another angle would need sin θ, which this calculator does not have. A comma and a period are the same B: 0,5 and 0.5.
B, I, and l must be positive. Typed 0 in any field gives F = 0: no field, no current, or no length in the field. All three fields need a number before 0.1 N can appear.
I = Q/t is on the neighbouring page: that I goes into the formula. Faraday is EMF from ΔΦ/Δt, volts, not newtons. F = m a is another path to the same unit N. Coulomb force is F = k q₁ q₂ / r², not B I l.
The calculator does not draw a right-hand rule. It computes the F magnitude at 90°. Direction stays with the problem.
Type 0.5, 2, and 0.1, click Calculate, and match 0.1 N. The header symbol does not pull the wire. Treat 0.1 N as the value at perpendicular B and I, not as a rail model.
F = B · I · l
Angle 90°. B > 0, I > 0, l > 0. Unit of F: newton.
Force on a straight wire at 90°: F = B·I·l. 0.5 T, 2 A and 0.1 m is 0.1 N. 1.5 T, 8 A and 0.2 m is 2.4 N.
B = 0.5 T, I = 2 A, l = 0.1 m -> F = 0.10 N.
B = 0.8 T, I = 0.5 A, l = 0.02 m -> F = 0.008 N.
B = 0.2 T, I = 10 A, l = 0.25 m -> F = 0.50 N.
B = 5e-5 T, I = 1 A, l = 1 m -> F = 0.00 N.
B = 1.2 T, I = 3 A, l = 0.15 m -> F = 0.54 N.
B = 0.4 T, I = 4 A, l = 0.05 m -> F = 0.08 N.
B = 0.5 T, I = 2 A, l = 0.4 m -> F = 0.40 N.
B = 1.5 T, I = 8 A, l = 0.2 m -> F = 2.40 N.
Force is 0.1 N. That is the product 0.5 × 2 × 0.1. The angle in this model is 90°, a full product with no sinφ.
Field B [T], current I [A], length l [m]. Result F [N]. Type a centimetre as 0.01, not as 1.
Force is 0 N. No current means no Lorentz force on the wire. The other two fields still need a number.
The calculator uses φ = 90°. At another angle sinφ enters and F drops. There is no angle field here.
Here force from a magnetic field, a current and a segment. There Newton’s second law, mass and acceleration. Different fields, same F [N].
Here a force on a current in field B. There a voltage from dB/dt or from motion. Another formula, another calculator.
Yes. 0.5 and 0,5 mean the same B [T]. F = B I l uses that field.
On the current-from-charge page. That I later enters F = B I l. Here current is an input, not a result.
Force is 0.5 N. 0.2 × 10 × 0.25, with the wire perpendicular to B.
You get 0.008 N. A weak current, a short segment, a small force.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.