Terminal speed calculator

Enter mass, area and the drag coefficient. You can leave air density blank: the calculator uses 1.225 kg/m³. Eighty kilograms, 0.5 m² and C = 1 give about 50.6 m/s.

Fall with no drag: h = ½gt². Density: ρ = m/V. Momentum: p = m·v.

Inputs

Result

Mass m (kg), Area S (m²), Coefficient C and Density ρ (kg/m³, blank = 1.225). The result shows up here.

How it works

mg ½ρCSv² v = √(2mg/(ρCS)) v_t ← m, S, C, ρ
Quadratic drag equals weight: that is terminal speed.

Terminal speed is where weight balances quadratic drag: mg = ½ ρ C S v², so v = √(2mg/(ρ C S)). The calculator keeps g at 9.81 m/s². When you leave ρ blank, we insert air at the ground, 1.225 kg/m³. That empty field is useful: most school problems want that air anyway.

A person of 80 kg, S = 0.5 m², C = 1 and blank ρ: v ≈ 50.6 m/s, about 182 km/h. With a 25 m² canopy and C = 1.4 you get about 6.05 m/s, already a parachute landing speed. A 1 kg ball, S = 0.01 m², C = 0.47: about 58.4 m/s.

Larger S or C pulls v down. Twice the area at the same mass cuts v by √2, not by half. Twice the mass at the same S raises v by √2. Water ρ, about 1000, is hundreds of times air: the same card gives another scale in water.

Free fall h = ½ g t² does not know air. Speed there grows without a ceiling. Here there is a ceiling. Momentum p = m v is a different quantity: 80 kg at 50.6 m/s is about 4050 kg·m/s, but you need this v first.

m, S and C must be positive. Typed 0 in C rejects the drag model. If you want a density other than air, type it on purpose, for example 1.2 or 1000. Leave ρ blank only when you really want 1.225.

Type m, S and C, leave ρ blank or give your own, then Calculate. The example 80, 0.5, 1 and blank ρ should come back near 50.61 m/s. A comma in 0.5 parses.

How to use

  1. Type mass in kilograms, for example 80, or 1 for a ball.
  2. Type area S in m² and C. A body is often 0.5 and C ≈ 1; a canopy 25 m² and C ≈ 1.4.
  3. You can leave density blank: then air is 1.225 kg/m³. Or type 1000 for water.
  4. Click Calculate. 80 kg, 0.5 m², C = 1 and blank ρ give about 50.6 m/s.
  5. For a fall with no air, open h = ½gt². Density from m and V lives on ρ = m/V.

Formula

v = √(2mg / (ρCS))

m > 0, S > 0, C > 0, ρ > 0. g = 9.81 m/s². Blank ρ = 1.225 kg/m³.

Letters in v = √(2mg/(ρCS))

This calculator finds terminal speed, where weight balances quadratic drag. 80 kg, 0.5 m² and C = 1 in 1.225 kg/m³ air is about 50.6 m/s.

v
Terminal speed in m/s. With 80 kg, S = 0.5 m² and C = 1 you get about 50.6 m/s; the calculator also shows km/h.
m
Mass in kilograms. A heavier body at the same area raises v. Eighty kilograms is the calculator example.
S
Cross-section facing the flow, in m². Half a square meter with C = 1 and 80 kg is that 50.6 m/s.
C
Dimensionless drag coefficient. C = 1 is a textbook blob, not a wind-tunnel reading.
ρ
Fluid density in kg/m³. A blank field inserts sea-level air, 1.225. Typing 1000 would be water.
g
Gravity, fixed at 9.81 m/s² in this calculator. You do not type it; it sits under the square root with 2m.

Real-life examples

Example 1

m = 80 kg, S = 0.5 m², C = 1, blank ρ -> v ≈ 50.61 m/s.

Example 2

m = 80 kg, S = 25 m², C = 1.4, blank ρ -> v ≈ 6.05 m/s.

Example 3

m = 1 kg, S = 0.01 m², C = 0.47, blank ρ -> v ≈ 58.38 m/s.

Example 4

m = 0.01 kg, S = 0.001 m², C = 0.5, blank ρ -> v ≈ 17.90 m/s.

Example 5

m = 0.005 kg, S = 0.06 m², C = 1.2, blank ρ -> v ≈ 1.05 m/s.

Example 6

m = 7 kg, S = 0.038 m², C = 0.47, blank ρ -> v ≈ 79.24 m/s.

Example 7

m = 80 kg, S = 0.5 m², C = 1, ρ = 1 kg/m³ -> v ≈ 56.03 m/s.

Example 8

m = 0.145 kg, S = 0.0043 m², C = 0.3, blank ρ -> v ≈ 42.43 m/s.

Ways to use this calculator

  • You compare 50.6 m/s of a body with 6.05 m/s under a 25 m² canopy.
  • You leave ρ blank for air, and type 1000 only when it really is water.

Frequently asked questions

How much v at 80 kg, S = 0.5 m², C = 1 and blank ρ?

v ≈ 50.6 m/s, about 182 km/h. Blank ρ is 1.225 kg/m³, air at the ground.

How much with a 25 m² canopy and C = 1.4 at the same mass?

v ≈ 6.05 m/s. Large S pulls terminal speed down to a parachute landing.

How much at 1 kg, S = 0.01 m² and C = 0.47?

v ≈ 58.4 m/s with blank ρ. Small ball, small area.

Why leave ρ blank?

Because most problems want air at 1.225 kg/m³. The empty field is a shortcut here, not missing data.

How is this different from h = ½gt²?

There is no air there, and v grows without end. Here there is a terminal speed, when drag matches weight.

Is momentum p = m v the same number?

No. Momentum of 80 kg at 50.6 m/s is about 4050 kg·m/s. Here you compute v; momentum is on its own card.

What if I type ρ = 1000?

That is the water scale. v drops sharply, because density is hundreds of times 1.225.

How does v change with S?

v falls as 1/√S. Twice S at fixed m gives v / √2, not half.

Can I change g?

The calculator keeps g = 9.81. Another planet is not in the fields.

Does a comma in 0.5 work?

Yes. 0,5 and 0.5 are the same S. A comma and a period mean the same value.

Knowledge sources

The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.

Page updated in 2026.