Example 1
- a = 10 · b = 6
≈ 188.495559
What is the ellipse area at a = 10 and b = 6? ≈ 188.495559.
Enter both semi-axes a and b (a > 0, b > 0). The result is the elliptical disk area A = π·a·b. With a = 10 and b = 6 you get 60π ≈ 188.495559. When a = b, the ellipse becomes a circle of area πa². Semi-axes are half-diameters — not full axes. The calculator does not compute ellipse perimeter or ellipsoid surface area.
Enter semi-axes a and b (a > 0, b > 0).
Semi-axes are half-diameters, not full diameters. The calculator does not compute perimeter. A circle from one radius is on the circle area page; a rectangle a·b without π is on the rectangle area page.
An ellipse is the set of plane points whose sum of distances from two foci is constant. The area inside an ellipse with semi-axes a and b is A = π·a·b. That is classical conic geometry: the formula generalizes the disk area πr² (when a = b = r) and follows from an affine map of the unit disk and from an integral along the semi-axes.
The domain is a > 0 and b > 0. Semi-axes are positive lengths — half-diameters, not full diameters. When a = b, the ellipse becomes a circle. Order of a and b does not change the product. The calculator uses the numbers a and b that you enter; the header unit switch only changes the cm²/in² label and does not convert entered values.
With a = 10 and b = 6: A = 60π ≈ 188.495559. A rectangle with those side lengths would have area 60. With a = b = 5: A = 25π ≈ 78.539816. With a = 8 and b = 3: A = 24π ≈ 75.398224. With a = 4 and b = 1: A = 4π ≈ 12.566371.
Affine derivation: the unit disk x² + y² ≤ 1 has area π. The map (x, y) ↦ (a x, b y) has determinant ab, so the image area is πab. Integral derivation: A = 4 ∫₀ᵃ b√(1 − x²/a²) dx = πab. Kepler described planetary orbits as ellipses (first law); orbital sector area ties to the second law of equal areas — this calculator still returns only the flat elliptical-disk area A = πab, not orbital parameters.
This calculator does not compute ellipse perimeter (elliptic integrals), ellipsoid surface area, or an elliptical sector. Applications include elliptical cross-sections, lenses in a simplified plane model, and comparison with a 2a-by-2b rectangle.
Check examples: a = 12 and b = 4 give 48π ≈ 150.796447; a = 7 and b = 2 give 14π ≈ 43.982297; a = 9 and b = 9 give 81π ≈ 254.469005; a = 15 and b = 5 give 75π ≈ 235.619449.
A = π · a · b, where a > 0 and b > 0.
Symbol a is the first semi-axis (first field). Symbol b is the second semi-axis (second field). The constant π comes from the disk-area definition. Computation: π · a · b; the panel also shows the product a·b and π·a·b as a check.
Mathematical model: ellipse area as π times the product of semi-axes (affine scaling of the unit disk / integral along a semi-axis; Kepler context — elliptical orbits).
An ellipse with semi-axes a and b (a > 0, b > 0) is the conic given in canonical form by x²/a² + y²/b² = 1. The area inside that ellipse is A = π·a·b. The symbols a and b are distances from the center to the boundary along the coordinate axes — halves of the major and minor diameters (or swapped when b > a). The calculator accepts both semi-axes and returns A.
The condition a > 0, b > 0 guarantees a positive area. When a = b the ellipse is a circle of radius a and A = πa². Confusing a diameter with a semi-axis inflates the result fourfold, because both lengths enter linearly.
Disk area A = πρ² is Archimedes’ result (Measurement of a Circle): the disk area equals the area of a triangle with base equal to the circumference and height equal to the radius. An ellipse arises from a circle by uniform “squeezing” (a linear map with constant determinant); the area scale factor is then |det|, so A_ellipse = π·a·b. Euclid’s Elements prepare conic geometry by exhaustion without modern algebra.
Johannes Kepler in Astronomia nova (1609) stated that planetary orbits are ellipses with the Sun at one focus (first law). The second law of equal areas concerns areal velocity about the focus — a different object from the ordinary elliptical-disk area πab. This calculator computes only A = πab for a plane ellipse with semi-axes a and b.
In applications an ellipse describes an oblique cylinder section, a lens outline in a 2D model, a Keplerian orbit in simplified form, and an error ellipse in statistics. Conceptually the formula counts plane area, not perimeter and not the surface area of a 3D ellipsoid.
Domain: a > 0, b > 0. The function A(a, b) = πab is increasing in each semi-axis separately. Homogeneity: scaling lengths by λ > 0 scales area by λ². Symmetry A(a, b) = A(b, a).
Eccentricity e = √(1 − (b_min/a_maj)²) with a_maj ≥ b_min measures flatness: e = 0 for a circle, e → 1⁻ for a very flat ellipse. Area does not depend on e directly — only on the product ab. The bounding rectangle with sides 2a and 2b has area 4ab, so the ellipse-to-rectangle area ratio is π/4.
As a → b⁺ one recovers A → πa² (a circle). As b → 0⁺ one has A → 0⁺.
Step 1. The unit disk x² + y² ≤ 1 has area π (Archimedes / π defined via disk area).
Step 2. The affine map T(x, y) = (a x, b y) has matrix diag(a, b) and |det T| = ab. Images of measurable sets scale 2D measure by ab, so the ellipse T(D) has area πab.
Step 3 (integral). From y = ±b√(1 − x²/a²) for |x| ≤ a: A = 2 ∫_{-a}^{a} b√(1 − x²/a²) dx. The substitution x = a sin θ or x = a cos θ yields A = πab.
Step 4 (check). When a = b = r, A = πr². When a = 10, b = 6, A = 60π ≈ 188.495559. Computation: π · a · b.
For a = 10, b = 6: A = 60π ≈ 188.495559. For a = b = 5: A = 25π ≈ 78.539816. For a = 8, b = 3: A = 24π ≈ 75.398224. For a = 4, b = 1: A = 4π ≈ 12.566371 — the formula does not require a ≈ b.
If the user supplies diameters D and d instead of semi-axes, A = (π/4)·D·d with D > 0, d > 0. Mixing diameter with semi-axis is the most common input mistake.
π·a·b is numerically stable for typical positive semi-axes in floating-point arithmetic range. Input with a ≤ 0 or b ≤ 0 is rejected. Comma and period are equivalent. The calculator does not model a rotated ellipse (axes not aligned with the coordinate axes) — that needs a quadratic form or a coordinate rotation before substituting a, b.
The calculator evaluates A = π · a · b after checking a > 0 and b > 0. With a = 10 and b = 6 the product of the semi-axes is 60, so A = 60π ≈ 188.495559 — the same value the result panel and the on-page example show. Field order does not change the product; the “semi-axis” labels stress that you enter half-diameters, not full diameters.
Ellipse perimeter P = 4a E(e) (complete elliptic integral of the second kind) is not computed. Ramanujan approximations and series are out of scope here. Eccentricity in the result panel is only a descriptive comment when a ≠ b.
In mechanics and optics ellipses appear for elliptical mirrors (reflections through the foci) and for pipe cross-sections. The moment of inertia of an elliptical disk about the center requires integrating ρ³ — that is not area. This calculator returns only A = πab.
Related models: circle area, rectangle area, circular annulus, circular sector. Ellipse area is not ellipsoid surface area (solid) and not a torus.
When a = b = r the formula reduces to A = πr² and matches the circle-area calculator at the same r. This page does not compute eccentricity e or a numerical arc-length integral — only the product of the semi-axes and π. Ellipse perimeter (Ramanujan-type approximations) lives on a separate page and does not enter this result.
Sources: Archimedes, Measurement of a Circle; Kepler, Astronomia nova (elliptical orbits); MathWorld — Ellipse; Wikipedia — Ellipse; NIST DLMF (π; elliptic integrals for perimeter — context only). The calculator is an educational tool.
Ellipse area is π·a·b. With a = 10 and b = 6 the result is ≈ 188.495559. Domain: a > 0, b > 0.
≈ 188.495559
What is the ellipse area at a = 10 and b = 6? ≈ 188.495559.
≈ 78.539816
What is the area at a = b = 5? ≈ 78.539816.
≈ 75.398224
What is the area at a = 8 and b = 3? ≈ 75.398224.
≈ 150.796447
What is the area at a = 12 and b = 4? ≈ 150.796447.
≈ 43.982297
What is the area at a = 7 and b = 2? ≈ 43.982297.
≈ 254.469005
What is the area at a = b = 9? ≈ 254.469005.
≈ 12.566371
What is the area at a = 4 and b = 1? ≈ 12.566371.
≈ 235.619449
What is the area at a = 15 and b = 5? ≈ 235.619449.
Enter both semi-axes a and b as positive lengths in the same unit. Semi-axes are half-diameters: a diameter of 20 means a = 10. If either value is missing, the calculator does not compute an area.
The result is π·10·6 = 60π ≈ 188.495559. That is the first worked example on this page and the same fill from “Fill this example”. A 10-by-6 rectangle would have area 60 — without π.
The ellipse becomes a circle of radius a. With a = b = 5 the result is 25π ≈ 78.539816, the ordinary disk area πr². The circle-area page computes the same quantity from one radius.
Not directly. Divide diameters by 2. Entering 20 and 12 as a and b inflates the result fourfold relative to the 10×6 ellipse, because both lengths enter A = πab linearly.
No. The unit switch only changes the cm² or in² label. Entered 10 and 6 still give ≈ 188.495559 in the chosen square scale. Both semi-axes must share the same length unit.
Yes. 2.5 and 2,5 are the same semi-axis. The calculator accepts a comma or a period as the decimal separator.
No. This calculator returns only the area A = πab. Ellipse perimeter has no elementary closed form (elliptic integrals / Ramanujan approximations) and needs a separate tool.
From an affine map of the unit disk: scaling the axes by a and b multiplies area by |det| = ab, so π·1·1·ab = πab. Equivalently the integral ∫_{-a}^{a} 2b√(1−x²/a²) dx yields the same value.
The result is 24π ≈ 75.398224. At a = 15 and b = 5 it is 75π ≈ 235.619449. In both cases that is πab, not the product a·b without π.
Not for the area. A = πab = πba. “Major / minor axis” labels only describe eccentricity; the product is unchanged.
The result is 4π ≈ 12.566371. That is a very flat ellipse; the formula does not require a to be close to b.
Not in this calculator. When a ≤ 0 or b ≤ 0, you get a domain error instead of a number. An empty field is not treated as zero.
Use A = π·a·b, where a and b are the semi-axes (half-diameters). With a = 10 and b = 6: π·10·6 = 60π ≈ 188.495559. Do not confuse semi-axes with full axes — that would make the result four times too large.
15π ≈ 47.123890. Enter a = 5 and b = 3. That is a classic oval-table example; the result is πab, not the 5×3 rectangle = 15.
No. Here only the flat area A = πab. Ellipse perimeter (elliptic integrals / Ramanujan) and 3D ellipsoid surface need other formulas — they are not on this card.
50π ≈ 157.079633. Enter a = 10 and b = 5. The ratio a/b = 2 describes a clearly elongated ellipse, but the area formula is still just πab.
A rectangle with sides a and b has area a·b. An ellipse inscribed in the 2a×2b bounding box has area πab — about 78.5% of that rectangle’s area, or π times the product of the semi-axes.
The ellipse definition and area formula below come from recognized mathematical sources.
Page Updated November 2, 2026.