Example 1
- a₁ = 2
- q = 3
- n = 4
54
What is the 4th term with a₁ = 2 and q = 3? 54. 2×3³.
Type the first term a₁, the ratio q and the index n. aₙ = a₁×qⁿ⁻¹. 2, 3 and 4 give 54. 1, 2 and 5 give 16. 5, 0.5 and 3 give 1.25.
n goes through max(1, the integer part of (n)). Typed 1.9 becomes 1. The result is raw, without trimming decimals. 5, 0.5 and 3 show 1.25.
Enter data and click Calculate.
The nth geometric term is the first term times the ratio to the power n−1. The calculator computes a₁×qⁿ⁻¹. 2, 3 and n = 4 give 2×27 = 54. The result goes in raw, not a trimmed decimal string.
The fields are a₁, q and n. The IDs stay a, b, c. 1, 2 and 5 give 16. 5, 0.5 and 3 give 1.25, because 5×0.25. n is cut with floor and never drops below 1.
Typed n = 0 or n = 0.4 becomes 1, so you get a₁ back. n = 4.9 becomes 4. q = −2 with a₁ = 3 and n = 4 would give −24. That is the its own card.
The nth arithmetic term adds r. The geometric series sum is on the neighbouring page and adds terms, it does not return one aₙ.
The header units switch does not multiply anything. 2, 3, 4 stay 54 whatever the label says.
2, 3 and 4 give 54. 1, 2 and 5 give 16. 5, 0.5 and 3 give 1.25.
aₙ = a₁ × qⁿ⁻¹, n = max(1, floor(n))
aₙ = a₁×qⁿ⁻¹. n = max(1, the integer part of (n)). 2, 3 and 4 give 54. 1, 2 and 5 give 16. 5, 0.5 and 3 give 1.25.
54
What is the 4th term with a₁ = 2 and q = 3? 54. 2×3³.
16
What is the 5th term with a₁ = 1 and q = 2? 16.
1.25
What is the 3rd term with a₁ = 5 and q = 0.5? 1.25. A raw JS fraction.
54. 2×3³ = 54.
Term number n in a sequence with a constant ratio q. aₙ = a₁×qⁿ⁻¹.
16. 1×2⁴ = 16.
1.25. 5×0.25. The calculator keeps the raw fraction.
n = max(1, the integer part of (n)). 4.9 becomes 4. 0 becomes 1 and returns a₁.
No. The calculator inserts the raw number. 1.25 stays 1.25.
The calculator multiplies by q. There you add r.
On the geometric series sum card. Here one aₙ.
Yes. q⁰ = 1, a₁ remains.
Yes. 3, −2 and n = 4 give −24.
The calculator computes the same formula as the definition below.
Page updated in 2026.