Arcsin Calculator

Enter x in [−1, 1] and choose degrees or radians. Inverse sine (arcsin) recovers the angle θ in [−90°, 90°] whose sine equals x. arcsin(0.5) = 30° = π/6. arcsin(1) = 90°. arcsin(0) = 0°.

Input

Result

Enter x between −1 and 1.

arcsin only works for x ∈ [−1, 1]. The result lies in [−90°, 90°] (−π/2 to π/2). Outside the domain there is no real sine value — the calculator reports an error instead of inventing an angle or showing a misleading zero.

How it works

How arcsin(0.5) is computed
x0.5
arcsinπ/6
θ30°

Inverse sine, written arcsin(x), asin(x), or sometimes sin⁻¹(x), is the inverse of sine on an interval where sine is one-to-one. Sine on the whole real line is periodic and not injective, so it has no unique inverse. On [−π/2, π/2], sin is continuous and strictly increasing from −1 to 1. Therefore there is a unique inverse arcsin : [−1, 1] → [−π/2, π/2] such that sin(arcsin(x)) = x and arcsin(sin θ) = θ for θ ∈ [−π/2, π/2]. That choice is the principal value and is the standard in NIST DLMF §4.23 and in Abramowitz and Stegun’s tables.

The domain is therefore [−1, 1]. The number 1.2 is not a real sine value, so the calculator rejects it instead of showing a misleading zero. The result range is [−π/2, π/2] in radians, or [−90°, 90°] in degrees. Landmark values: arcsin(0) = 0, arcsin(1) = π/2, arcsin(−1) = −π/2, arcsin(1/2) = π/6, arcsin(√2/2) = π/4, arcsin(√3/2) = π/3, arcsin(−1/2) = −π/6.

The calculator uses the number x you enter in the “Value x (sine)” field and the result-unit switch. The calculator computes arcsin(x) in radians in [−π/2, π/2], then — when you choose degrees — multiplies by 180/π. For x = 0.5 the degree result is 30°, and in radians π/6 ≈ 0.523599. A comma and a period in the x field are equivalent.

The link to arccos follows from the identity: for x ∈ [−1, 1], arcsin(x) + arccos(x) = π/2, so arcsin(x) = π/2 − arccos(x). Sine oddness gives arcsin(−x) = −arcsin(x). On the principal branch the cosine of θ = arcsin(x) is nonnegative: cos θ = √(1 − x²). On (−1, 1) you also have arcsin(x) = arctan(x/√(1 − x²)). Those relations let you check the result: sin θ returns x, and π/2 − arccos(x) must match arcsin(x).

The derivative, integral, and series belong to standard calculus. For |x| < 1, (arcsin x)′ = 1/√(1 − x²); at the domain endpoints the derivative has vertical asymptotes. The indefinite integral ∫ arcsin(x) dx = x·arcsin(x) + √(1 − x²) + C appears via integration by parts. The Maclaurin series arcsin(x) = x + (1/2)(x³/3) + (1·3)/(2·4)(x⁵/5) + … converges for |x| ≤ 1 and is the classical expansion in tables. In numerical practice asin is often reduced to atan; the principal-branch result matches arcsin.

In geometry arcsin appears for an angle from a side ratio: in a right triangle sin θ = opposite / hypotenuse, so θ = arcsin(a/c) when |a/c| ≤ 1. In a 3-4-5 triangle the ratio 3/5 = 0.6 gives θ ≈ 36.8699°. In physics Snell’s law and projectile angles are often written with arcsin. This calculator does not compute sides or speeds — only θ = arcsin(x) from one argument.

Formula

θ = arcsin(x), where x ∈ [−1, 1] and θ ∈ [−π/2, π/2].

In degrees: θ° = arcsin(x) · (180 / π). The symbol x is the sine value you enter (the “Value x (sine)” field). The symbol θ is the principal angle. The constant π comes from the radian definition (a half-turn). Computation: arcsin(x) in radians, then optional multiplication by 180/π.

Mathematical model: principal branch of inverse sine (principal arcsin), following the NIST Digital Library of Mathematical Functions, §4.23, and Abramowitz and Stegun’s classical tables (Chapter 4).

Theory, identities, and derivatives

Definition

The inverse sine, written arcsin(x) or asin(x), is the inverse of the restriction of sine to an interval on which sine is one-to-one. The map sin : ℝ → [−1, 1] is periodic and is not injective on the whole real line: sin(θ) = sin(π − θ) = sin(θ + 2πk) for integers k. Hence no global single-valued inverse exists. On the closed interval [−π/2, π/2], sin is continuous and strictly increasing from −1 to 1, so it is bijective onto [−1, 1]. The inverse of that restriction is arcsin : [−1, 1] → [−π/2, π/2].

The range [−π/2, π/2] is the principal value. It is the standard branch in the NIST Digital Library of Mathematical Functions, §4.23, and in Abramowitz and Stegun, Handbook of Mathematical Functions, Chapter 4. In degrees the principal range is [−90°, 90°]. This calculator uses the same branch: it computes arcsin in radians and, when requested, converts α° = α · (180/π).

Historical and conceptual context

Inverse trigonometric functions arose wherever an angle must be recovered from a sine value — in astronomy, surveying, and calculus. In modern analysis arcsin is one of the six standard inverse trigonometric functions. MathWorld treats Inverse Sine as multi-valued in the complex plane, with a distinguished real branch on [−1, 1].

Conceptually, arcsin does not select an angle outside the principal branch. For x = 1/2 both 30° and 150° have sine equal to 1/2, yet arcsin(1/2) = π/6. That choice is an analytic convention: it preserves oddness (arcsin(−x) = −arcsin(x)) and continuity on the whole domain. When a two-argument angle from (cos, sin) with quadrant resolution is required, atan2 is used rather than arcsin alone.

Formal properties

Domain: x ∈ [−1, 1]. A number outside this interval is not a real sine value, so no real result exists. Codomain (principal range): [−π/2, π/2]. The function arcsin is continuous on [−1, 1], strictly increasing, with arcsin(−1) = −π/2, arcsin(0) = 0, arcsin(1) = π/2. It is an odd function.

Identities for x ∈ [−1, 1]: sin(arcsin(x)) = x; arcsin(sin θ) = θ for θ ∈ [−π/2, π/2]; arcsin(x) + arccos(x) = π/2; arcsin(−x) = −arcsin(x); cos(arcsin(x)) = √(1 − x²) ≥ 0 on the principal branch.

Derivative: for |x| < 1, (arcsin x)′ = 1/√(1 − x²). At the endpoints the derivative has vertical asymptotes. Antiderivative: ∫ arcsin(x) dx = x·arcsin(x) + √(1 − x²) + C. These formulas match NIST DLMF §4.23 and Abramowitz & Stegun.

Full derivation of the branch and the derivative

Step 1. Let f(θ) = sin θ on [−π/2, π/2]. Then f′(θ) = cos θ ≥ 0 and is strictly positive on (−π/2, π/2), so f is strictly increasing. Since f(−π/2) = −1 and f(π/2) = 1, the image is [−1, 1].

Step 2. Therefore a unique inverse g : [−1, 1] → [−π/2, π/2] exists. Write g = arcsin. By definition, sin(arcsin(x)) = x and arcsin(sin θ) = θ on the indicated sets.

Step 3 (derivative). Let y = arcsin(x), so x = sin y. Differentiating in y yields dx/dy = cos y, hence dy/dx = 1/cos y. On (−π/2, π/2), cos y > 0 and cos y = √(1 − x²), so (arcsin x)′ = 1/√(1 − x²).

Step 4 (link to arccos). Let β = arccos(x) ∈ [0, π]. Then sin(π/2 − β) = x and π/2 − β ∈ [−π/2, π/2]. Uniqueness of arcsin gives arcsin(x) = π/2 − arccos(x), so arcsin(x) + arccos(x) = π/2.

Special cases

Standard values: arcsin(−1) = −π/2; arcsin(−√3/2) = −π/3; arcsin(−√2/2) = −π/4; arcsin(−1/2) = −π/6; arcsin(0) = 0; arcsin(1/2) = π/6; arcsin(√2/2) = π/4; arcsin(√3/2) = π/3; arcsin(1) = π/2. For x = 0.6 (the 3/5 ratio from a 3-4-5 triangle) the result is arcsin(0.6) ≈ 0.6435 rad ≈ 36.87°.

As x → ±1 the angle approaches ±π/2 and sensitivity (the derivative) grows without bound. Near |x| = 1 a small change in x produces a large change in angle — a geometric feature of the unit circle, not a calculator defect. For |x| > 1 no real result exists.

Numerical and computational notes

The browser uses arcsin (floating-point arithmetic, about 15–16 significant digits). In numerical literature the angle from (√(1−x²), x) is sometimes computed as atan2(x, √(1−x²)), which recovers the same [−π/2, π/2] branch and can be better conditioned near the endpoints. This calculator reports arcsin — the same principal value.

Input outside [−1, 1] is rejected with an error message; the calculator does not return a complex arcsin. A comma or a period in the field is accepted equivalently. Near |x| = 1, loss of precision in √(1−x²) in floating-point arithmetic is a known numerical caveat.

Related concepts and authorities

Related tools on this site: inverse cosine (range [0, π]), inverse tangent, sine of an angle (the forward map), and the degrees–radians converter. Arcsin does not compute triangle side lengths — use the law of sines for that.

Authorities: NIST DLMF §4.23; Abramowitz & Stegun, Chapter 4; MathWorld — Inverse Sine; Wikipedia — Inverse trigonometric functions (principal ranges). The calculator is educational and does not replace a textbook.

How to use

  1. Enter x in Value x (sine), from −1 to 1, for example 0.5.
  2. Choose Show result in: Degrees (°) or Radians.
  3. Click Calculate or wait for the live result. 0.5 gives 30°. 1 gives 90°. 0 gives 0°. −0.5 in radians gives −π/6.
  4. Check the panel: degrees, radians, √(1 − x²), the sin θ check, π/2 − arccos(x), and the arctan form. The unit-circle diagram draws angle θ.
  5. x outside [−1, 1] is rejected. Bare sine of an angle lives on the sine page — here you go from a value to an angle.

Symbol glossary

arcsin recovers the angle whose sine is x. arcsin(0.5) = 30°. Domain [−1, 1], principal range [−90°, 90°].

arcsin
Principal inverse sine: arcsin : [−1, 1] → [−π/2, π/2]. Input only from −1 to 1. arcsin(0.5) = 30°, arcsin(−1) = −π/2.
x
The sine value in the “Value x (sine)” field. 0.5, 0, 1, or −1. 1.2 is rejected, because it is not a real sine.
θ
The result angle on the principal branch. Degrees or radians per the switch. Always in [−90°, 90°].
√(1−x²)
cos θ on the principal branch. For x = 0.5 it equals √0.75 ≈ 0.866025.

Examples

Example 1

  • x: 0.5 · degrees

30°

What is arcsin(0.5)? 30° = π/6.

Example 2

  • x: 1 · degrees

90°

What is arcsin(1)? 90° = π/2.

Example 3

  • x: 0 · degrees

0°

What is arcsin(0)? 0°.

Example 4

  • x: −0.5 · radians

−π/6 ≈ −0.523599

What is arcsin(−0.5)? −30° = −π/6.

Example 5

  • x: −1 · degrees

−90°

What is arcsin(−1)? −90° = −π/2.

Example 6

  • x: 0.866 · degrees

≈ 60°

What is arcsin(√3/2) ≈ arcsin(0.866)? ≈ 60°.

Example 7

  • x: 0.707 · degrees

≈ 45°

What is arcsin(√2/2) ≈ arcsin(0.707)? ≈ 45°.

Example 8

  • x: 0.6 · degrees

≈ 36.87°

What is arcsin(0.6) from a 3-4-5 triangle? ≈ 36.87°.

Related calculators

Frequently asked questions

What are the domain and range of arcsin?

The domain is the closed interval [−1, 1]: only those numbers are sine values in the reals. The principal-value range is [−π/2, π/2] in radians, or [−90°, 90°] in degrees. Outside [−1, 1] there is no real result — the calculator shows an error, not a fake angle or a zero.

What is arcsin(0.5)?

The angle is 30°, because sin 30° = 1/2. In radians that is π/6 ≈ 0.523599. That is the first worked example on this page and the same fill from “Fill this example”.

What are arcsin(1) and arcsin(0)?

arcsin(1) = 90° (π/2 rad), arcsin(0) = 0°. Those are the upper end of the principal range and zero. arcsin(−1) = −90° (−π/2).

Why is the result never 150°?

By definition the principal value of arcsin is restricted to [−90°, 90°]. The angle 150° shares sine with 30°, but it is not on the principal branch. The calculator picks 30° from x = 0.5, matching NIST DLMF 4.23.

How do I switch the result to radians?

In “Show result in”, choose Radians. Then 30° becomes π/6 ≈ 0.523599, and 90° becomes π/2. The result panel also always shows the other unit beside the primary field.

How does arcsin differ from sine and from arccos?

Sine goes from angle to number: sin 30° = 0.5. Arcsin goes the other way: 0.5 returns 30°. Arccos inverts cosine and has range [0°, 180°]. For x ∈ [−1, 1], arcsin(x) + arccos(x) = π/2.

What is arcsin(−0.5)?

The angle is −30° (−π/6 rad). A negative sine lands below the axis, still inside [−90°, 90°]. Oddness gives arcsin(−x) = −arcsin(x).

What angle comes from x = 0.6 in a 3-4-5 triangle?

About 36.8699°. In a 3-4-5 right triangle the opposite-over-hypotenuse ratio is 3/5 = 0.6, so θ = arcsin(0.6). The calculator computes the angle, not the sides.

How do the derivative, series, and arctan form work?

For |x| less than 1 the derivative is (arcsin x)′ = 1/√(1 − x²). The Maclaurin series is arcsin(x) = x + (1/2)(x³/3) + (1·3)/(2·4)(x⁵/5) + … for |x| ≤ 1. On (−1, 1) you also have arcsin(x) = arctan(x/√(1 − x²)). Those formulas appear in NIST DLMF §4.23–4.24 and Abramowitz and Stegun, Chapter 4.

Do the currency and unit settings in the page header affect the result?

No. The result depends only on x and on the degrees/radians switch in the form. The currency and unit settings in the page header do not affect this result.

Does sin⁻¹(x) mean 1/sin x?

No. In many textbooks sin⁻¹(x) means arcsin(x), not cosecant. Cosecant is 1/sin x and uses csc. This calculator returns an angle, not a reciprocal quotient.

Why is there no longer a zero outside the domain?

An earlier version of the calculator returned 0 for |x| greater than 1, which looked like arcsin(0). The calculator now reports an error: outside [−1, 1] no real sine value exists.

How do I calculate arcsin?

Enter x in [−1, 1]. The result is the angle θ ∈ [−90°, 90°] such that sin θ = x. For 0.5 you get 30° (π/6); for 1 — 90°; for −0.5 — −30°. Outside [−1, 1] there is no real result.

What is arcsin (inverse sine)?

Arcsin, arcsine, or sin⁻¹ is the inverse of sine on [−π/2, π/2]. From a number in [−1, 1] it returns the principal angle. Do not confuse it with hyperbolic sine or with area sine (arsinh).

What is arcsin(√2/2)?

45° = π/4, because sin 45° = √2/2 ≈ 0.707. The page has an example with x ≈ 0.707 — the same angle after “Fill this example”.

Can I compute arcsin of a number greater than 1?

Not in the reals. Sine never exceeds 1 or falls below −1, so the domain of arcsin is [−1, 1]. For |x| > 1 the calculator shows an error, not a fake angle.

What is arcsin(√3/2)?

60° = π/3, because sin 60° = √3/2 ≈ 0.866. The example with x ≈ 0.866 on the page gives about 60°.

The result is the principal arcsin value: for x = 0.5 the angle is 30° (π/6). The sin θ check returns x. A separate inverse cosine lives on the arccos page.

Knowledge sources

Definitions, domain, range, and identities below come from established mathematical references.

Page Updated November 2, 2026.