Example 1
Circular orbit at Earth’s surface: M = {{u:5.972e24:mass:0}}, r = {{u:6371000:dist-m:0}}. This is the reference value; the period is 84.3 min.
v₁ = 7.91 km/s
Enter the mass M of the central body and the orbit radius r measured from its center; the constant G can stay empty. The calculator finds the circular orbital speed with v₁ = √(GM/r) and also reports the orbital period, the escape speed v₂ = v₁·√2, the parameter GM, and the gravitational acceleration at that point. For Earth (5.972·10²⁴ kg, 6,371 km) the result is 7.91 km/s. The model does not include an elliptical vis-viva speed, a Hohmann transfer, or the third cosmic velocity.
Enter the mass M and the orbit radius r. Orbital speed, period, and the v₁(r) chart will appear here.
Escape speed is on the escape velocity calculator; the two speeds are related by v₂ = v₁·√2. Centripetal acceleration on this circle is a = v₁²/r, and the field is g = GM/r². The force between two masses is on the gravitational force calculator.
The first cosmic velocity is the speed of a circular orbit at a distance r from the center of a mass M. Gravity then supplies exactly the centripetal acceleration: GM/r² = v₁²/r, so v₁ = √(GM/r). The satellite’s mass cancels, so a bolt and a space station on the same orbit need the same speed. This is a textbook result of Newtonian mechanics (Halliday, Resnick, and Walker; Young and Freedman). In Newton’s cannon thought experiment from De mundi systemate, the shot that falls around the Earth closes this circle.
The calculator uses three numbers: the gravitational constant G (an empty field means 6.67430·10⁻¹¹ N·m²/kg²), the mass M in kilograms, and the radius r in meters. It computes GM, then GM/r, then the square root. For Earth: GM = 3.986·10¹⁴ m³/s², GM/r = 6.256·10⁷ m²/s², and v₁ = 7,910 m/s, or 7.91 km/s (4.91 mi/s). The period T = 2πr/v₁ is 84.3 min. For the Moon (7.35·10²² kg, 1,737 km) the result is 1.68 km/s.
What the result panel shows. Besides v₁ in km/s, the calculator reports the same speed in m/s and km/h, the time for one revolution, the escape speed v₂ = v₁·√2 (11.19 km/s for Earth), the parameter GM, the gravitational acceleration GM/r² (9.82 m/s² at Earth’s surface), the multiple of Earth’s circular speed, and the entered M and r. The chart shows v₁ falling with radius as 1/√r: twice the distance from the center cuts the speed by √2, not by half, and multiplies the period by 2√2.
Limits of the model. The formula describes a point mass or a spherically symmetric body, and a satellite whose mass is negligible beside M. It assumes a circle, no atmosphere, and no rotation of the central body. The calculator does not compute speed on an ellipse (the vis-viva equation), a Hohmann transfer, or the third cosmic velocity. It also does not add the roughly 0.465 km/s that Earth’s spin gives to an eastward launch from the equator. A grazing orbit just above the surface is only a model: air and mountains stop it. The ISS, at r = 6,771 km, moves at 7.67 km/s with a period of 92.4 min.
The unit switch in the header changes the fields to pounds and feet, and the speeds to mi/s, ft/s, and mph; the numbers in the text stay in SI as the reference. Large values can be entered in scientific notation (5.972e24). Mass and radius must be greater than zero: without mass there is no field, and a radius of zero would mean an infinite speed.
Examples on this page: Earth’s surface → 7.91 km/s; the ISS orbit (r = 6,771 km) → 7.67 km/s; the Moon → 1.68 km/s; Mars → 3.55 km/s; two Earth radii → 5.59 km/s; geostationary orbit → 3.07 km/s; Earth’s orbit around the Sun → 29.79 km/s. The button “Fill this example” enters the same numbers and refreshes the result panel and the chart.
v₁ = √(GM / r)
[v₁] = √((N·m²/kg²)·kg / m) = √(m²/s²) = m/s; T = 2π√(r³/GM), v₂ = v₁·√2, g = GM/r²
Model: circular orbital speed from equating gravity and the centripetal force (I. Newton, Principia, 1687; GMm/r² = mv₁²/r). The period T = 2πr/v₁ is Kepler’s third law for a circle. The rearrangements r = GM/v₁² and M = v₁²r/G follow from the same equation, but this calculator returns only v₁. Order of operations: GM, then GM/r in SI units, the square root, then T = 2πr/v₁, v₂ = v₁·√2, and g = GM/r².
The first cosmic velocity is the speed at which a body in the gravitational field of a mass M closes a circular orbit of radius r and needs no further thrust to stay on it. Gravity is then the only centripetal force. The total energy on that orbit is negative and equal to −GMm/(2r): in the sense of the virial theorem, half of the potential energy has become kinetic energy. A slower body falls on an ellipse or a straight line. A faster body, up to v₂, is still bound, but the path becomes an ellipse with one focus at the center of mass.
Three properties follow. First, v₁ does not depend on the satellite’s mass. Second, the velocity is tangent to the path: the radial component is zero, or the radius would grow or shrink. Third, v₁ falls as 1/√r and the period grows as r to the power 3/2. A geostationary satellite is therefore slower than the ISS, even though it orbits much higher, and its period matches a sidereal day.
Johannes Kepler, in Harmonices mundi (1619), wrote that the square of the orbital period is proportional to the cube of the mean distance from the Sun. Isaac Newton showed in the Principia (1687) that this proportion follows from a force that falls as 1/r². The thought experiment of a shot from a high mountain, described in De mundi systemate (1728), separates two thresholds: the speed at which the cannonball circles the Earth, and the higher speed at which it never returns. The name “first cosmic velocity” is the school term in Polish and Russian; English textbooks usually say circular orbital speed.
The first artificial satellite of Earth was Sputnik 1, launched on October 4, 1957, into low Earth orbit. The speed of such an orbit is closer to the 7.67 km/s of the ISS example than to the textbook 7.91 km/s computed at the surface itself. The surface result remains a reference, not a flight plan.
Step 1. The gravitational force on a satellite of mass m is F = GMm/r². Step 2. On a circle that same force is the centripetal force mv₁²/r, so GMm/r² = mv₁²/r. Step 3. Cancel m (m > 0) and multiply both sides by r: v₁² = GM/r, so v₁ = √(GM/r). Step 4. For Earth, with G = 6.67430·10⁻¹¹ N·m²/kg², M = 5.972·10²⁴ kg, and r = 6.371·10⁶ m, GM = 3.986·10¹⁴ m³/s² and v₁ = 7,910 m/s.
The period comes from the circumference: T = 2πr/v₁ = 2π√(r³/GM). At Earth’s surface that is 84.3 min. Substituting r = 42,164 km gives 23.9 h, the sidereal day of a geostationary orbit in this model. Written through g = GM/r², the same formula is v₁ = √(gr). At Earth’s surface, √(9.82·6.371·10⁶) returns 7.91 km/s.
The second cosmic velocity, v₂ = √(2GM/r), comes from energy, not from the centripetal force, and it is exactly √2 times v₁. For Earth, 7.91 km/s·√2 = 11.19 km/s. The kinetic energy of escape is twice the kinetic energy of the circular orbit, because the speed rises only by 41 percent while energy rises with the square of speed. Between v₁ and v₂ the path is an ellipse. Speed on an ellipse follows the vis-viva equation v = √[GM(2/r − 1/a)], which this calculator does not evaluate.
The third cosmic velocity, about 16.7 km/s relative to Earth, is enough to leave the Solar System. It is not the sum of v₁ and Earth’s speed around the Sun. The calculator does report Earth’s circular speed at 1 AU (29.79 km/s) as an example that uses the solar mass, without adding vectors.
By Newton’s shell theorem, the field outside a spherically symmetric body is the field of a point with the same mass. Earth is oblate, so a real GM and real orbits need geopotential harmonics; the school square root does not see them. The satellite’s mass must be much smaller than M. For two comparable bodies the numerator is M + m.
The model ignores air. At the altitude of the ISS drag is small, but it is enough that the station loses altitude without corrections. An eastward launch from the equator adds about 0.465 km/s relative to the ground, yet v₁ in this calculator is the speed relative to the inertial center of mass, not relative to the launch site. A rocket does not reach orbit with a finished v₁ at the ground: it accelerates gradually and meets the speed that belongs to its r only after it is above the dense atmosphere.
The definition, the derivation, and the numbers come from mechanics textbooks and metrology sources: I. Newton, Philosophiae Naturalis Principia Mathematica, 1687, and De mundi systemate, 1728; J. Kepler, Harmonices mundi, 1619; D. Halliday, R. Resnick, and J. Walker, Fundamentals of Physics, gravitation; H. D. Young and R. A. Freedman, University Physics, “Gravitation”; R. P. Feynman, R. B. Leighton, and M. Sands, The Feynman Lectures on Physics, Vol. I, Chapter 7; H. D. Curtis, Orbital Mechanics for Engineering Students, Butterworth-Heinemann; CODATA 2018 (NIST) for G; NASA Planetary Fact Sheets. This page is educational.
v₁ is the circular orbital speed, G the gravitational constant, M the mass of the central body, and r the radius measured from the center. For Earth the result is 7.91 km/s.
Circular orbit at Earth’s surface: M = {{u:5.972e24:mass:0}}, r = {{u:6371000:dist-m:0}}. This is the reference value; the period is 84.3 min.
v₁ = 7.91 km/s
The International Space Station, 400 km above Earth, so r = {{u:6771000:dist-m:0}}. One revolution takes 92.4 min.
v₁ = 7.67 km/s
A low orbit above the Moon, measured from the center: M = {{u:7.35e22:mass:0}}, r = {{u:1737000:dist-m:0}}. The Moon has no atmosphere, so a surface-grazing path is closer to the model than it is on Earth.
v₁ = 1.68 km/s
A circular orbit at the surface of Mars: M = {{u:6.39e23:mass:0}}, r = {{u:3390000:dist-m:0}}. That is less than half of Earth’s 7.91 km/s.
v₁ = 3.55 km/s
Two Earth radii from the center (r = {{u:12742000:dist-m:0}}). The speed is exactly √2 times smaller than the surface orbit.
v₁ = 5.59 km/s
Geostationary orbit, r = {{u:42164000:dist-m:0}}. The satellite completes one revolution in 23.9 h and stays above one meridian.
v₁ = 3.07 km/s
Earth’s circular orbit around the Sun at the 1 AU scale (r = {{u:1.496e11:dist-m:0}}, M = {{u:1.989e30:mass:0}}). The period in this model is 365.2 days. It is a circle, not Kepler’s exact ellipse.
v₁ = 29.79 km/s
A classroom problem with the rounded constant G = 6.67·10⁻¹¹ N·m²/kg² at Earth’s surface. In meters per second the result is about 3 m/s lower than with the CODATA value of G; in kilometers per second it still reads 7.91.
v₁ = 7.91 km/s
The calculator finds the first cosmic velocity, the speed of a circular orbit, from v₁ = √(GM/r). It multiplies G by the mass M, divides the product by the radius r, and takes the square root. For Earth (5.972·10²⁴ kg, 6,371 km) it returns 7.91 km/s, and the orbital period is 84.3 min.
By default, mass is in kilograms, radius in meters, and G in N·m²/kg²; the result is in km/s and also in m/s and km/h. After you switch the header to US units, mass is in pounds, radius in feet, and speeds in mi/s, ft/s, and mph. Scientific notation, for example 5.972e24, is allowed.
No. An empty field means the CODATA 2018 value, 6.67430·10⁻¹¹ N·m²/kg². Enter your own value only when the problem states a rounded constant, for example 6.67·10⁻¹¹; for Earth that changes the result by about 3 m/s.
The first, v₁ = √(GM/r), keeps a body on a circular orbit. The second, v₂ = √(2GM/r), lets it recede to infinity. The relation is exact: v₂ = v₁·√2. For Earth, v₁ = 7.91 km/s and v₂ = 11.19 km/s; the panel shows both, and the primary result remains the orbital speed.
No. In the force equation GMm/r² = mv₁²/r the satellite’s mass cancels, so a bolt and a space station on the same orbit have the same speed. Mass changes the kinetic energy and the propellant required, not v₁ itself.
Because r in the formula is the distance from the center of mass. For an orbit at the surface, r equals the radius of the body. For the ISS, an altitude of 400 km is added to 6,371 km, so r = 6,771 km and v₁ = 7.67 km/s.
In the model, yes; in an atmosphere, no. Air and terrain stop that path. A real low orbit sits higher, which is why the ISS at r = 6,771 km moves at 7.67 km/s rather than 7.91 km/s.
It is the time for one revolution, T = 2πr/v₁, which is Kepler’s third law for a circle, T = 2π√(r³/GM). At Earth’s surface it is 84.3 min, on the ISS orbit 92.4 min, and on a geostationary orbit 23.9 h.
It is the product of the gravitational constant and the mass of the central body, called μ in astrodynamics. For Earth, it is 3.986·10¹⁴ m³/s². Satellite tracking determines it more precisely than G alone or the mass alone, so engineers compute orbits from GM directly.
It does not compute elliptical orbits from the vis-viva equation, a Hohmann transfer, or the third cosmic velocity. It does not include air drag, and it does not add Earth’s rotational speed, about 0.465 km/s for an eastward launch from the equator.
Multiply G by M, divide by r, and take the square root. For Earth at 5.972×10²⁴ kg and r = 6,371,000 m the result is about 7.91 km/s.
About 7.91 km/s. At r = 6,771 km (ISS order) the speed falls to about 7.67 km/s and the period rises to about 92 min.
Add the altitude to the body radius: r = R + h. The formula uses distance from the center, not height above the ground alone.
No. The main result is circular v₁. The vis-viva form v = √(GM(2/r − 1/a)) is not a mode on this page.
v₁ sustains a circular orbit at a given r. Hohmann is two burns between orbits. The third cosmic velocity is about leaving the Solar System. This page only computes √(GM/r).
The definition, the unit, the history, and the derivation below come from standard physics and metrology sources.
Page updated November 3, 2026.