Example 1
Earth M and R: v₁ ≈ 7.9 km/s.
Enter the planet mass and the orbit radius. You get the circular-orbit speed. Earth at r = 6371 km is 7.91 km/s. Higher, at r = 6771 km, v₁ falls to 7.67 km/s.
In orbit a = v₁²/r = GM/r²: centripetal acceleration and g. Force: centripetal = gravity. Escape: v₂ = v₁√2.
Constant G (N·m²/kg², optional), Mass M (kg) and Orbit radius r (m). The result shows up here.
First cosmic velocity is the speed on a circular orbit. Gravity supplies the inward acceleration, so GM/r² = v₁²/r. That is v₁ = √(GM/r). Typing G, M, and r separately shows where the number comes from, better than a single GM product.
At Earth’s surface r = 6.371×10⁶ m and M = 5.972×10²⁴ kg. GM/r = 6.256×10⁷, the square root is 7910 m/s, or 7.91 km/s. School 7.9 km/s is a rounding. The formula has no atmosphere: you still cannot fly just above the ground.
On LEO r = 6.771×10⁶ m, v₁ = 7670 m/s, about 7.67 km/s. Larger r in the denominator under the root means a smaller speed. At geosynchronous r ≈ 4.216×10⁷ m, v₁ falls to about 3.07 km/s.
Satellite mass cancels. The same v₁ for 1 kg and for a station. The inward force is gravity, also written F = m v₁²/r. Escape from the well is v₂ = v₁√2, about 11.19 km/s at the same surface.
M and r must be positive. Empty G = 6.67430×10⁻¹¹. The result is in m/s. The calculator also shows km/h or mph from the header. A comma and a period in 5.972e24 both parse.
The chart of v₁(r) at fixed M falls. Twice the r cuts v₁ by √2, not by half. Escape speed and g itself live on the neighboring pages, with the same M and r.
v1 = √(GM / r)
Equivalently v12 / r = GM / r2 (centripetal a = g).
Circular orbit: v₁ = √(GM/r). Earth at r = 6371 km is 7.91 km/s; higher, at r = 6771 km, v₁ falls to 7.67 km/s.
Earth M and R: v₁ ≈ 7.9 km/s.
r ≈ 6771000 m.
r ≈ 6871000 m.
M ≈ 7.35e+22 kg, r ≈ 1837000 m.
M ≈ 6.39e+23 kg, r ≈ 3390000 m.
r ≈ 42164000 m.
r = 12742000 m.
Earth orbit around the Sun (scale).
G = 6.67e-11, Earth surface.
r = 6800000 m.
7910 m/s, or 7.91 km/s. On LEO at 6771 km it is 7.67 km/s.
No. Satellite mass cancels. You are left with √(GM/r).
In orbit a = v₁²/r = GM/r². That is the same g, written through speed.
The formula says yes. Atmosphere and mountains say no. Real orbits sit higher, hence 7.67 km/s on LEO, not 7.91.
v₂ = v₁√2. From 7.91 km/s you get 11.19 km/s. A separate page computes √(2GM/r).
M ≈ 7.35×10²² kg gives about 1.63 km/s. Mars at the surface is about 3.55 km/s.
The calculator needs G, M, and r separately. The product still happens inside. That way you can change G or M.
M_☉ ≈ 1.989×10³⁰ kg, r ≈ 1.496×10¹¹ m, v₁ ≈ 29.8 km/s. Scale, not a precise ellipse.
Yes. At fixed M, larger r gives smaller v₁, like 1/√r.
F = GMm/r² = m v₁²/r. Gravity and centripetal force are the same pair on a circle.
The formula is the school one. Units follow SI; NIST SP 330 and BIPM define the measures, not your result.
Page updated in 2026.